All categories

3 years ago

Alex and Peter win some money and share it in the ratio 6:1. Alex gets £50 more than Peter. How much did they get altogether?

Mathematics

2 answers:

Alex Ar [27]3 years ago

6 0

Alex = 6x
Peter = x

6x = x + 50
5x = 50
x = 10

Alex = £60
Peter = £10

together = £70

Brums [2.3K]3 years ago

5 0

Ratio

Alex : Peter : Total
6 . : 1 : 7

Difference in shares = 6 - 1 = 5
5 shares = £50

1 share = £50 ÷ 5
1 share = £10

7 shares = £10 x 7 = £70

---------------------------------------------
Answer: They get £70 altogether.
---------------------------------------------

You might be interested in

I really need help with this question, pls help!!

Marrrta [24]

Answer:

Step-by-step explanation:

Here the average rate of change would be

f(6) - f(1) 162 - (-8)

a. r. of c. = ----------- = ------------------ = 154/5 = 308/10 = 30.8 or 30 8/10

6-1 5 or 30 4/5

6 0

3 years ago

HELP PLEASE ILL TRY TO MARK U BRAINLIEST

Anon25 [30]

Step-by-step explanation and answer:

For this you just need to plug in x for y = f(1/5x)

1/5(-4) = -4/5 or -0.8

1/5(-1) = -1/5 or -0.2

1/5(0) = 0

1/5(3) = 3/5 or 0.6

1/5(6) = 6/5 or 1.2 or 1 1/5

4 0

2 years ago

A bag contains 5 white, 3 black, and 2 green balls. Balls are picked at random.

Soloha48 [4]

Answer:

look down there

Step-by-step explanation:

First ball:

Probability of drawing a white ball is 5/8

Probability of drawing a black ball is 3/8

Second ball:

This depends on the first ball drawn, lets say you drew a white ball initially, 4 white balls are left out of 7 balls in total. The probability of a white ball in the second pick is 4/7.

Total probability of drawing two white balls is 5/8*4/7 (since they are independent events).

If you picked a black ball initially, picking another black ball would have a probability of 2/7, on similar grounds , total prob for 2 blacks would be 3/8*2/7.

The probability that you pick 2 balls of same color is (5/14 + 3/28) = 13/28. (Since they are mutually exclusive events)

6 0

3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .