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Gelneren [198K]

3 years ago

6

In a small community college lecture hall there are 13 rows of seats , for the first four rows the number of seats are 10,14,18,

22,.... How many seats does the last row have

2 answers:

antoniya [11.8K]3 years ago

8 0

The answer is 58...
hope this helps

enot [183]3 years ago

3 0

There will be 58 seats in the last row. You just find the number of seats added to each row than add it up till you get to the 13'th row

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Dafna1 [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

The ____ are two straight dotted lines, one horizontal and one vertical.

Airida [17]

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5 0

3 years ago

Simplify the expression 3(x + 9) by distributing. Which expression is equivalent?

notsponge [240]

3(x+9)

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3x+27

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8 0

3 years ago

The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

49243

Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

7 0

3 years ago

Add 1} + (-5) using the number line.

gizmo_the_mogwai [7]

Answer:

1/2

Step-by-step explanation:

1 1/3+(-5/6)

1 1/3=4/3

4/3+(-5/6)

4/3-5/6

8/6-5/6

3/6

simplify

1/2

6 0

3 years ago