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Sedbober [7]
3 years ago
14

LMN is a right a right angle triangle angle NLM is 90 degrees PQ is parallel to LM. Area of triangle PNQ is 8cm and area of tria

ngle LPQ is 16 cm work out area of LQM

Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer: 48cm^2

Step-by-step explanation:

LMN is a right a right angle triangle angle NLM is 90 degrees PQ is parallel to LM. Area of triangle PNQ is 8cm and area of triangle LPQ is 16 cm work out area of LQM

Kindly see attached picture for detailed explanation

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Vanyuwa [196]

Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

                      =  6² + 6²

                      = 36 + 36

                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

the other two sides are 6 and  6\sqrt{2}

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

                       3 d = 4

therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

                                     =\frac{8}{3}

the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

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Answer:

According to the given problems the one that gets closer is the first option. ^12sqrt27/2

Step-by-step explanation:

<em>Simplify the radical by breaking the radicand up into a product of known factors.</em>

The answer for the first question is 12 √ 27 / 2


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