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Sonbull [250]
3 years ago
9

What is the simplest form of 3 square root 27 a^3b^7?

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0
\sqrt[3]{27a^3b^7} = \sqrt[3]{3^3 \cdot a^3 \cdot b^6 \cdot b^} = 3ab^2(\sqrt[3]{b} )
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Answer:

We conclude that:

  • g(10) = 8

Step-by-step explanation:

First, we need to clear some concepts on how to fetch input and output from the function graph.

Determining the y-intercept:

We know that the y-intercept of the graph function can be determined by setting x = 0 and determining the corresponding y-value.

From the graph it is clear that x = 0, the value of y = 5. In other words, the graph intersects the y-axis at y = 5.

Therefore, the y-intercept of the graph is (0, 5).

Thus,

  • g(0) = 5

Determining the x-intercept:

We know that the x-intercept of the graph function can be determined by setting y = 0 and determining the corresponding x-value.

From the graph, it is clear that y = 0, the value of x = -10. In other words, the graph intersects the x-axis at x = -10.

Therefore, the x-intercept of the graph is (-10, 0).

Thus,

  • g(-10) = 0

Determining g(10):

From the graph, it is clearly visible that at x = 10, the value of the function output y = 8.

In other words,

  • at x = 10, g(10) = 8

Therefore, we conclude that:

  • g(10) = 8
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Step-by-step explanation:

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