3 years ago

What is the simplest form of 3 square root 27 a^3b^7?

1 answer:

5 0

$\sqrt[3]{27a^3b^7} = \sqrt[3]{3^3 \cdot a^3 \cdot b^6 \cdot b^} = 3ab^2(\sqrt[3]{b} )$

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Lorico [155]

Answer:

C - 1 / sin^2x

Step-by-step explanation:

as csc x = 1 / sin x

so, csc^2 x = 1 / sin^ 2x

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2 years ago

allsm [11]

18/7 or 2 4/7 bc 3/7 times 6 is 18/7 or 2 and 4/7

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2 years ago

Rudik [331]

Answer: In attached

Step-by-step explanation:

Use the given functions to set up and simplify

Attachment has your answer.

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2 years ago

Xelga [282]

It’s false because if you take a negative number away from another negative number it would give you another negative number not a positive number!

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2 years ago

Naddik [55]

Answer:

Step-by-step explanation:

a) To find the length of diagonal XT, we can use the distance formula to get $\sqrt{(-3-5)^{2}+(4-(-2))^{2}}=10$

Since this is a rectangle, XT=YW, meaning YW=10 as well.

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c) The perimeter is just 2(8+6)=28.

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2 years ago