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3 years ago

6(x – 1) = 9(x + 2) what is the answer

Mathematics

1 answer:

const2013 [10]3 years ago

6 0

Answer:

The answer is x = -8

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What are the coordinates of the point on the directed line segment from (-6, -3)(−6,−3) to (-1, 7)(−1,7) that partitions the seg

rosijanka [135]

Answer:

(-3,3).

Step-by-step explanation:

The given points are (-6,-3) and (-1,7).

We need to find the coordinates of the point, which divides the line segment in 3:2.

Section formula: If a point divides a line in m:n, then the coordinates of point are

$\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Using this formula, we get

$\left(\dfrac{3(-1)+2(-6)}{3+2},\dfrac{3(7)+2(-3)}{3+2}\right)$

$\left(\dfrac{-3-12}{5},\dfrac{21-6}{5}\right)$

$\left(\dfrac{-15}{5},\dfrac{15}{5}\right)$

$\left(-3,3\right)$

Therefore, the coordinates of required point are (-3,3).

8 0

3 years ago

V = u + at<br> u = 2 a = -7 t = 0.5

VashaNatasha [74]

v= u+ at

just put value bruuhh u can't even do this? alright

v=2+ (-7)(0.5)

v= -1.5

8 0

3 years ago

PLSSSSSSSSSSSSSSSSSSSSSS HELP

jek_recluse [69]

2a + 3b, 6ab, And 2b + 3a

5 0

3 years ago

Read 2 more answers

How do you get high marks on a test??? Quickkk

Fed [463]

Answer:

Revise

Step-by-step explanation:

Practice, ask if you don't understand, keep watching videos if you don't get it.

If you don't understand a question, ask for help!

Hope this helped!

5 0

3 years ago

Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

nalin [4]

For each $1\le i\le n$ , $E[X_i]=0$ , so that

$\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0$

Meanwhile,

$\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]$

Each of the $X_i$ have PDF

$f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}$

for $x\in\Bbb R$ . From this we get

$E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}$

$\implies E[Y_2]=n\sqrt{\dfrac2\pi}$

8 0

3 years ago