All categories

3 years ago

The circle (x + 2)2 + (y - 5)2 = 9 is shifted 3 units up and 2 units to the right. What is the equation of the new circle?

Mathematics

2 answers:

Jobisdone [24]3 years ago

4 0

Answer:

Hey there,

Let's get started !

First, read the rules which are in the attachement.

Then,

(x+2)² + (y-5)² = 9

will become :

(x+2-2)² + (y-5-3) = 9

x² + (y-8)² = 9

In short, the answer would be the option A.

Hope this helps !

Step-by-step explanation:

mrk branliest plz

Naya [18.7K]3 years ago

4 0

Answer:

answer would be A

Step-by-step explanation:

You might be interested in

Solve for y X+y=6 X=4 Simplify your answer as much as possible Will give Brainliest

maw [93]

Answer and workin your attached below. Hope it helps

5 0

2 years ago

Read 2 more answers

-7z - 7 ≤ -5z + 5 need help sloving

V125BC [204]

-7z - 7 ≤ -5z + 5

- 7 - 5 ≤ -5z + 7z
-12 ≤ 2z
-12/2 ≤ z
-6 ≤ z or z>= -6

7 0

3 years ago

Read 2 more answers

Solve for x -4(5 - x) = (x + 7)

garik1379 [7]

Answer:

x=9

Step-by-step explanation:

4 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers

Helpp me out pls!!!!!!!!!

dsp73

Answer:

a. Maurice walked farther.

b. 0.62 m

Step-by-step explanation:

Maurice

4.1 × 1.8 = 7.38 miles

Junnie

2.5 × 3.2 = 8 miles

This shows that Junnie walked more than Maurice.

8 - 7.38 = 0.62

Junnie walked 0.62 m more than Maurice

5 0

3 years ago