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IceJOKER [234]
4 years ago
5

a square poster of length 3x is going to have a square painting centered on it. The length of the painting is 2x. the area of th

e poster not covered by the painting will be painted black. what is the area of the poster that will be painted black?
Mathematics
1 answer:
eduard4 years ago
3 0
One way to solve this is to look at the size of the poster, and then subtract the size of the picture so you have the area that needs to be painted left.

Area of square poster - 3x × 3x = 9x^2
Area of painting - 2x × 2x = 4x^2

9x^2 - 4x^2 = 5x^2

The area is 5x^2
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Could I get some help?
balandron [24]

Answer:

#adult tickets sold = 346

#student tickets sold = 812

Step-by-step explanation:

let 'x' = # adult tickets sold

let 'y' = # students tickets sold

System of Equations:

x + y = 1158

5x + y = 2542

I used the elimination method and multiplied the first equation by -1

  -x - y = -1158

+<u> 5x + y = 2542</u>

  4x  =  1384

   x = 346

346 + y = 1158

y = 812

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3 years ago
laryy has 3 packets of ballons with 15 ballons in each packet. he wants to put the same number of balloons into 10 gift bags wha
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larry has 3 packer sin each 15 and total are 45 u wish put in 10 bags then divide 45 by 10 anser is 5

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3 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

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1 year ago
I hate how i have to write things here
Harlamova29_29 [7]

Answer: Question 1 is m=-7/4

Question 2 is -4 as the y axis where it intercepts and the other coordinate is (3,-2)

Step-by-step explanation:

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3 years ago
Find the y-intercept of the line on the graph.​
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The y intercept is 2,0
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