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IceJOKER [234]
3 years ago
5

a square poster of length 3x is going to have a square painting centered on it. The length of the painting is 2x. the area of th

e poster not covered by the painting will be painted black. what is the area of the poster that will be painted black?
Mathematics
1 answer:
eduard3 years ago
3 0
One way to solve this is to look at the size of the poster, and then subtract the size of the picture so you have the area that needs to be painted left.

Area of square poster - 3x × 3x = 9x^2
Area of painting - 2x × 2x = 4x^2

9x^2 - 4x^2 = 5x^2

The area is 5x^2
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Drake's Drugstore is getting ready for the upcoming summer season. The manager of the store wants to
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22222222222222222 not 3 and not 1

Step-by-step explanation:

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A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
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Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

(  x  - 300 )  , and the price decrease

(1/80)*40  =  0,5

Then the demand function is:

D(x)  =  600  - 0,5* ( x - 300 )  (1)

And revenue function is:

R(x) =  x * (D(x)   ⇒   R(x) =  x* [  600  - 0,5* ( x - 300 )]

R(x) = 600*x  - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x  - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) =  450  - x

R´(x) =  0       ⇒   450  - x = 0

x = 450 units

We can observe that for   0 < x  < 450  R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450)  =  600  - 0,5* ( x - 300 )

D(450)  =  600 - 225 + 150

D(450)  =

D(450)  =  600 - 0,5*( 150)

D(450)  =  600 - 75

D(450)  = 525

And the rebate must be

600 - 525  = 75 $

5 0
3 years ago
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