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Olegator [25]
3 years ago
15

Write and graph an equation to represent the situation.

Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0

464 divide by 16 is 29. So y would be 29


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In the triangle below, what is csc θ?
earnstyle [38]
It si cool so basicly u take 5 divide bye 13 times 5

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3 years ago
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Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).
ki77a [65]

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

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3 years ago
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Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
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The expression 12(x + 4) represents the total cost of CDs Mei bought in April and May at $12 each. Which property is applied to
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D because you have to distribute the twelve to complete the equation
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Which of the pictures below shows the graph of the inequality y≥x+2?
Oduvanchick [21]

Answer: i think its B not sure tho

Step-by-step explanation:

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