This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
The range is 19-0=19 so therefore your answer is C.
The range is the largest number subtracted by the smallest number.
Answer:
8/3mph
Step-by-step explanation:
you must multiply both fractions by the reciprocal of 3/10 which is 10/3
(4/5 * 10/3) / (3/10 * 10/3)
(40/15) / (30/30)
(8/3) / 1
8/3 /1 = 8/3
5: THEO = what should happen
EXP = Wha actually happens.