You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)
Answer:
You will need 20 sides to complete the loop.
Step-by-step explanation:
The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop
We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV
With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.
108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.
This means that each polygon is rotated 18 degrees relative to it's neighbour.
With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.
Answer:
Zero
Step-by-step explanation:
3x - 7 = 3x - 9 + 2
3x - 7 = 3x - 7
Add 7 on both sides
3x = 3x
Subtract 3x you get 0.
Hope this helps.
Answer:
Step-by-step explanation:
Given
x ----- y
0.5. --- 0.8
1. --- 1.6
3.--- 4.8
25. --- 40
Required
Determine the constant of proportionality
This can be calculated using the following formula:
; Where r is the constant of proportionality;
Solve for r
When x = 0.5; y = 0.8
When x = 1; y =1.6
When x = 3; y = 4.8
When x = 25; y = 40
Notice that the value of r is constant throughout;
Hence:
