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Harrizon [31]
3 years ago
15

A classmate simplifies the expression in exercise 1. is the expression he wrote equivalent to the original expression? explain.

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0
Excercise 1:

No, this is not simplified fully. The full answer would be <span>−7dk+14d−21k</span>−7, not <span>14d - 9 - 21k - 7dk + 2. So, it is not equivalent.
</span><span>
Excercise 4:
</span><span>7dk (2 - 3 - 1) - 7
</span>
Just multiply 7dk into (2) (-3) and (-1)
you'd get:
<span><span>−<span>14dk</span></span>+</span>−<span>7 after simplifying it fully.
</span>
p = parameter
w = width

w+2.75

p = 2w+2(w+2.75) = <span>4w</span>+<span>5.5 = 30

Answer to the last one:

w = 6.125</span>
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Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z

Total defects=Production*Probability

                      =0.3174*1000

                       =317.4

b. \mu=10,\sigma=0.05

therefore:-

z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z

Defects=Probability*Production

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             =2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

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If you vertically compress the square root parent function f(x) = ^x, by 1/2 of a unit what is the equation of the new function
Naddik [55]

Answer:

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Step-by-step explanation:

Suppose we have a function f(x).

a*f(x), a > 1, is vertically stretching f(x) a units. Otherwise, if a < 1, we are vertically compressing f(x) by a units.

f(x - a) is shifting f(x) a units to the right.

f(x + a) is shifting f(x) a units to the left

In this question:

f(x) = \sqrt{x}

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