Use binomial distribution, with p=0.20, n=20, x=3
P(X=x)=C(n,x)p^x (1-p)^(n-x)
P(X>=3)
=1-(P(X=0)+P(X=1)+P(X=2))
=1-(C(20,0)0.2^0 (0.8)^(20-0)+C(20,1)0.2^1 (0.8)^(20-1)+C(20,2)0.2^2 (0.8)^(20-2))
=1-(0.0115292+0.057646+0.136909)
=1-0.206085
=0.793915
Answer:
c) 
Step-by-step explanation:
−2 = −⅔[5] + b
−3⅓
1⅓ = b
y = −⅔x + 1⅓
Then convert to Standard Form:
y = −⅔x + 1⅓
+⅔x + ⅔x
__________
⅔x + y = 1⅓ [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
3[⅔x + y = 1⅓]
* 1⅓ = 4⁄3
I am joyous to assist you anytime.
B. represents a dialation
Answer:
0.15651
Step-by-step explanation:
This can be approximated using a Poisson distribution formula.
The Poisson distribution formula is given by
P(X = x) = (e^-λ)(λˣ)/x!
P(X ≤ x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)
where λ = mean of distribution = 20 red bags of skittles (20% of 100 bags of skittles means 20 red bags of skittles)
x = variable whose probability is required = less than 16 red bags of skittles
P(X < x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to (x-1))
P(X < 16) = Σ (e^-λ)(λˣ)/x! (Summation From x=0 to x=15)
P(X < 16) = P(X=0) + P(X=1) + P(X=2) +......+ P(X=15)
Solving this,
P(X < 16) = 0.15651
Answer:
The last term is 33.
Step-by-step explanation:
Sn = (n/2)(a1 + L) where a1 = first term and L = the last.
So:
-480 = (20/2) ( -81 + L)
-480 = 10( L - 81)
L- 81 = -480 / 10 = -48
L = -48 + 81
L = 33.
