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butalik [34]
2 years ago
12

Permutations of the word "Congratulations"​

Mathematics
1 answer:
Mice21 [21]2 years ago
5 0

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is  14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is  14!/(23)=10,897,286,400

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Tatiana [17]
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
6 0
3 years ago
X^2 - 4x - 4y = 0 in standard form
DENIUS [597]

Answer: y= 1/4x^2-x

I  guess

3 0
3 years ago
A clown bought 6 bags of round balloons with 24 balloons in each bag.The clown also bought 3 bags of long balloons with 36 ballo
Ierofanga [76]
6 bags × 24 balloons = the amount of round balloons
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3 bags × 36 balloons = the amount of long balloons
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108 long balloons - 144 round balloons = number of more long balloons that round ones
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He has -36 more long balloons that round ones
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7 0
3 years ago
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Katen [24]
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3 years ago
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Consider a right triangle that has these dimensions: the side opposite angle a is 6 meters and the side adjacent angle a is 8 me
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To determine the length of the hypotenuse, we need a relation that would relate the other legs and the hypotenuse of the triangle. So, we would need to use the Pythagorean theorem which is an equation that relates the hypotenuse with the other legs of a right triangle. It is to be noted that this is only usable for right triangles only. It is expressed as follows:

c^2 = a^2 + b^2

where c is the hypotenuse and a, b are the other legs.

c = √(a^2 + b^2)
c = √(6^2 + 8^2)
c = √100
c = 10 m

Therefore, the length of the hypotenuse with the other legs having a length of 6 and 8 would be 10 m.
5 0
3 years ago
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