I'm guessing the question is meant to be "<span>If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.
Area of a circle =</span>πr^2
5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2
Formula for triangle area = base times height over two. area of smallest triangle: 2*2/2, so 2. area of medium sized triangle: 2*6/2, so 6. the square in between those triangles has an area of four (2*2). the base of the largest triangle is 2+2+6, so 10, and the height is 4. use the formula to find its area is 20. add them all together to get 4+6+4+20 is 34 units^2.
Answer:
2,674.14 g
Step-by-step explanation:
Recall that the formula for radioactive decay is
N = N₀ e^(-λt)
where,
N is the amount left at time t
N₀ is the initial amount when t=0, (given as 42,784 g)
λ = coefficient of radioactive decay
= 0.693 ÷ Half Life
= 0.693 ÷ 18
= 0.0385
t = time elapsed (given as 72 years)
e = exponential constant ( approx 2.7183)
If we substitute these into our equation:
N = N₀ e^(-λt)
= (42,787) (2.7183)^[(-0.0385)(72)]
= (42,787) (2.7183)^(-2.7726)
= (42,787) (0.0625)
= 2,674.14 g
14= 7+7
16= 8+8
18= 9+9
20= 9+11
22= 10+12
24= 12+12
26= 7+8+11
