Answer:
Possible locker numbers for Selma are: 3, 5 and 29
Step-by-step explanation:
First of all, let us have a look at the definition of a prime number.
A <em>prime number</em> is a number which is divisible either by 1 or the number itself.
No other number divides the prime number other than 1 and the number itself.
Now, let us factorize the given number 435 and let us observe the what all possibilities are there.
Factorizing 145 further:
No further factors are possible.
Therefore 3, 5 and 29 are the prime factors of 435.
So, the answer is:
Possible locker numbers for Selma are: 3, 5 and 29
Answer: its 62
Step-by-step explanation:
Isolate the radical, then raise each side of the equation to the power of its index.
Answer:
for no 7 its none for 8 its st
Step-by-step explanation:
I hope this helps
Answer: 19 cm
<u>Step-by-step explanation:</u>
99 =
99 =
198 = (2x + 13)(x - 4)
198 = 2x² + 5x - 52
0 = 2x² + 5x - 250
0 = 2x²- 20x + 25x - 250
0 = 2x(x - 10) + 25( x - 10)
0 = (2x + 25)(x - 10)
0 = 2x + 25 or 0 = x - 10
= x or x = 10
Since length cannot be negative, can be disregarded
Larger base: x + 9 = 10 + 9 = 19
The temperature would be (21.5 + 6.25) which is 27.75