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Nadusha1986 [10]
3 years ago
6

Someone please help me! thank you so much

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0
Hello,

I believe the answer would be 5. Let me explain.

For the equation f(x) = -2x +3, I plugged in "-1" from the ordered pair into the equation as "x".

f(x) = -2 (-1) +3, and that would simplify to f(x) = 5,

so then y = 5.

Hope this helps!

May
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on the playground 1/4 kids are on the jingle gym and 1/3pm are playing kick ball.how many kids are on the jungle gym or playing
DaniilM [7]
1/12 kids are playing on the playground
3 0
3 years ago
Is the number 17 a prime or composite number?
Alborosie

Answer:

It is a prime number.

Step-by-step explanation:

A prime number is a number that can only be the product of 1 and itself. 17 can only be multiplied by 1 and 17, so it is prime.

7 0
3 years ago
The price of an item selling at 150% of its $63 value is
Triss [41]
You just have to multiply the percentage by the amount:
(150/100)×$63 
1.5×$63= $94.50
If you aren't allowed a calculator, then just find half of $63 (the 0.5 of the fraction) and add it to $63 (the 1. of the fraction).
$63÷2= $31.5
$63+$31.5= $94.50
8 0
4 years ago
Read 2 more answers
en un maratòn participan corredores de todos los continentes 5/6 de los corredores son europeos se sabe que los americanos son l
Marysya12 [62]

Usando proporciones, se encuentra que 400 africanos han participado.

En total, hay x participantes.

\frac{5}{6} de los corredores son europeos, o sea:

E = \frac{5x}{6}

Los americanos son la dècime parte de los europeos, o sea:

Am = \frac{1}{10}E = \frac{5x}{60} = \frac{x}{12}

Los africanos son la quinta parte de los americanos, o sea:

Afr = \frac{1}{5}Am = \frac{x}{60}

En la carrera han inscritos 24 000 participantes, o sea, x = 24000. Por eso, la cantidad de africanos es:

Afr = \frac{x}{60} = \frac{24000}{60} = 400

Para obtener más información sobre las proporciones, puedes visitar a brainly.com/question/24615636

8 0
2 years ago
Consider the equation below.
Korvikt [17]

Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71

y=3(x+5)^2-75+71

So, we get equation as

y=3(x+5)^2-4

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

now, we can compare and find h and k

y=3(x+5)^2-4

we get

h=-5

k=-4

so, extreme value of this equation is

(h,k)=(-5,-4)

6 0
4 years ago
Read 2 more answers
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