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sergij07 [2.7K]
3 years ago
7

Lim x->infinity (1+1/n)

Mathematics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=1

Step-by-step explanation:

We want to evaluate the following limit.


^{ \lim}_{n \to \infty} (1+\frac{1}{n})


We need to recall that, limit of a sum is the sum of the limit.


So we need to find each individual limit and add them up.

^{ \lim}_{n \to \infty} (1+\frac{1}{n})=^{ \lim}_{n \to \infty} (1) +^{ \lim}_{n \to \infty} \frac{1}{n}


Recall that, as n\rightarrow \infty,\frac{1}{n} \rightarrow 0 and the limit of a constant, gives the same constant value.



This implies that,


^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1 +0


This gives us,

^{ \lim}_{n \to \infty} (1+\frac{1}{n})= 1


The correct answer is D



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In a certain population of the eastern thwump bird, the wingspan of the individual birds follows an approximately normal distrib
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a) P(48 < x < 58) = 0.576

b) P(X ≥ 1) = 0.9863

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Step-by-step explanation:

The mean of the wingspan of the birds = μ = 53.0 mm

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To solve this, we first normalize/standardize the two wingspans concerned.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

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We'll use data from the normal probability table for these probabilities

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b) The probability that at least one of the five birds has a wingspan between 48 and 58 mm = 1 - (Probability that none of the five birds has a wingspan between 48 and 58 mm)

P(X ≥ 1) = 1 - P(X=0)

Probability that none of the five birds have a wingspan between 48 and 58 mm is a binomial distribution problem.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of birds = 5

x = Number of successes required = number of birds with wingspan between 48 mm and 58 mm = 0

p = probability of success = Probability of one bird having wingspan between 48 mm and 58 mm = 0.576

q = probability of failure = Probability of one bird not having wingspan between 48 mm and 58 mm = 1 - 0.576 = 0.424

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p = probability of success = Probability of one bird having wingspan less than 48 mm = 0.212

q = probability of failure = Probability of one bird not having wingspan less than 48 mm = 1 - p = 0.788

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P(X > 2) = 0.05916433913 + 0.00795865476 + 0.00042823218

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