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Answer:
1- Option A = Sink
2- Option B = Float
Explanation:
1- If an object’s density is greater than 1.00 g/mL, it will sink in water.
For example, the density of aluminum is 2.7g/cm³. That is why it will sink in water.
2- If an object’s density is less than 1.00 g/mL, it will float in water.
For example, the density of oak is 0.7 g/cm³. That is why oak will float in water.
3- Given data:
Mass, m = 50 g
Volume, v = 10 cm3 ( 1ml = 1cm3)
Formula of density :
Density = mass/ volume
d = m/v
d = 50g/10cm3
d = 5 g/cm3
Answer:
1000 g
Explanation:
Given data:
Initial temperature of water = 45°C
Final temperature of water = 25°C
Heat released = 20 cal (4184×20 = 83680 j)
Mass of water = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.184 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25°C - 45°C
ΔT = -20°C
83680 j = m × 4.184 j/g.°C ×20°C
83680 j = m × 83.68 j/g
m = 83680 j / 83.68 j/g
m = 1000 g
<span>0.0797 g
Looking at the formula, 1 mole of KIO3 and 5 moles of KI will react and produce moles of iodine molecules or 6 moles of iodine atoms. So first, determine the number of moles of KIO3 and KI provided
moles KIO3 = 0.0121 * 0.097 = 0.0011737 mol
moles KI = 0.0308 * 0.017 = 0.0005236 mol
The limiting reactant is KI at 0.0005236 mol so divide by 5 and multiply by 6 to get the number of moles of iodine atoms.
0.0005236 / 5 * 6 = 0.00062832 mol
Lookup the atomic weight of iodine which is 126.90447
And multiply that by the number of moles of iodine produced
126.90447 g/mol * 0.00062832 mol = 0.079736617 g
Rounding to 4 decimal places gives 0.0797 g</span>
