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2 years ago

58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?

Chemistry

1 answer:

podryga [215]2 years ago

7 0

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

moles of $K_2SO_4$ = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg$

Therefore, the molality of solution is 0.66 mole/kg

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For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g

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Answer: $Rate=k[O_3][NO_2]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

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$NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)$ fast

To determine the net chemical equation, we will simply add the above two equations, we get:

$O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)$

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3 years ago

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Explanation:

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3 years ago

When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo

Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

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From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

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3 years ago

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Answer:

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1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

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1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

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3 years ago