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Natalija [7]
2 years ago
10

58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?

Chemistry
1 answer:
podryga [215]2 years ago
7 0

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

moles of K_2SO_4 = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg

Therefore, the molality of solution is 0.66 mole/kg

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For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g
zavuch27 [327]

Answer: Rate=k[O_3][NO_2]^2

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)   slow

NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)   fast

To determine the net chemical equation, we will simply add the above two equations, we get:

O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)

Rate=k[O_3][NO_2]^2

Order with respect to O_3 is 1 and Order with respect to NO_2 is 2.

Thus the rate law will be:  Rate=k[O_3][NO_2]^2

6 0
3 years ago
When the white part is on the left the moon is.??​
Kazeer [188]

Answer:

Last Quarter also called Third Quarter.

Explanation:

6 0
3 years ago
When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo
Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

b)

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

3 0
3 years ago
One way to heat a gas is to compress it. a gas at 1.00 atm at 25.0°c is compressed to one tenth of its original volume, and it r
Tanzania [10]

(p1)(V1)/(T1) = (p2)(V2)/(T2)
(1.00 atm)(V) / (273 + 25K) = (40.0 atm)(V/10) / (273 + T)
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Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

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First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
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