Question

58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?

Answer 1

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

moles of $K_2SO_4$ = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg$

Therefore, the molality of solution is 0.66 mole/kg