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2 years ago

Calculate the pH when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10⁻⁴).

1 answer:

8 0

When a volume of 60.0 mL of 0.200 M HBr is mixed with a volume of 30.0 mL of 0.400 M CH3NH2, The pH value is mathematically given as

pH=10.64

<h3>What is the pH value when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂?</h3>

Question Parameters:

The pH when 60.0 mL of 0.200 M HBr

30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10^{-4}).

Generally, the equation for the Chemical Reaction is mathematically given as

H Br + H_3C NH_2----- > CH_3 NH_3 Br

Therefore

oH=p^{kb}+-log $\frac{salt}{base}$

OH=-log(4.4*10^{-4})+ $\frac{0.1}{0.1}$

OH=3.36

In conclusion, The equation pH value

pH+OH=14

Therefore

pH+=14-3.36

pH=10.64

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3 years ago

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A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2

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From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

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We have to use the formula;

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1 year ago

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

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Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

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$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

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2 years ago

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2 years ago