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3 years ago

Calculate the pH when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10⁻⁴).

1 answer:

8 0

When a volume of 60.0 mL of 0.200 M HBr is mixed with a volume of 30.0 mL of 0.400 M CH3NH2, The pH value is mathematically given as

pH=10.64

<h3>What is the pH value when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂?</h3>

Question Parameters:

The pH when 60.0 mL of 0.200 M HBr

30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10^{-4}).

Generally, the equation for the Chemical Reaction is mathematically given as

H Br + H_3C NH_2----- > CH_3 NH_3 Br

Therefore

oH=p^{kb}+-log $\frac{salt}{base}$

OH=-log(4.4*10^{-4})+ $\frac{0.1}{0.1}$

OH=3.36

In conclusion, The equation pH value

pH+OH=14

Therefore

pH+=14-3.36

pH=10.64

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When temperatures are below freezing, the temperature at which air becomes saturated leading to the formation of frost is the

12345 [234]

Answer:

The answer is Frost Point.

Explanation:

The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.

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4 years ago

what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg

zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

<u>Step 1:</u> Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

<u>Step 2:</u> Calculate the number of moles

PV = nRT

⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

<u>Step 3</u>: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

<u>Step 4:</u> Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F = 3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

<u>Step 5:</u> Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

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3 years ago

Is this an alpha or beta decay?

4vir4ik [10]

Answer:

alpha decay

Explanation:

5 0

3 years ago

Read 2 more answers

Calcula la cantidad de gramos que hay en 12,5 mol de NaCl (Masa Na: 23,0; Cl: 35,5).

Anon25 [30]

Answer:

731.25 g

Explanation:

The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;

Molar mass of sodium chloride= 23.0 + 35.5 = 58.5 gmol-1

From the formula;

Number of moles (n) = mass /molar mass

Number of moles of sodium chloride= 12.5 moles

Mass of sodium = The unknown

Molar mass of sodium chloride= 58.5gmol-1

Mass of sodium chloride= number of moles × molar mass

Mass of sodium chloride= 12.5 × 58.5

Mass of sodium chloride= 731.25 g

4 0

3 years ago

If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity

Ksju [112]

<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

Number of moles = Mass /molar mass

= (10.7g NH4Cl)/(53.5g/mol NH4Cl)

= 0.200 moles NH4Cl

Then we convert to liters:

= (800mL)*(1L/1000mL) = 0.800L

Therefore; molarity = 0.2moles/0.8L

= 0.25M

4 0

3 years ago