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Mademuasel [1]
3 years ago
11

parallelogram ABCD has vertices A(-2,-51/2), B(-4,-51/2), C(-3,-2), and D(-1,-2). find the vertices of parallelogram A'B'C'D' af

ter a translation of 2 1/2 units down.

Mathematics
1 answer:
Volgvan3 years ago
7 0
On a coordinate plane, any movement up and down is on the y-axis. So if your parallelogram is moving down 2.5 units, then the y-values of each vertice will go down by 2.5:
A(-2, -8), B(-4, -8), C(-3, -4.5), D(-1, -4.5)

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amm1812
It is 4170 I believe if my calculations are correct
5 0
3 years ago
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Hey please answer the questions on attachment, thank you very much- i need it in 10 minutes and am completely clueless.
nevsk [136]

Answer:

5x+17

Step-by-step explanation:

2(x+7) + 3(x+1)

  1. Distribute(Expand) -> 2x+14 + 3x+3
  2. Simplify by combining like terms -> 5x+17
7 0
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In a right-angled triangle, the hypotenuse is 113 and a leg is 112.
melomori [17]

Answer: 15

Step-by-step explanation: Use the formula: a^{2}+b^{2}=c^{2}

Remember c^{2} should always be the hypotenuse or the longest side.

112^{2}+b^{2}=113^{2} ---> evaluate the exponents

12544+b^{2}=12769 ----> subtract 12544 to the other side

b^{2}=225 ---> take the square root of both sides

b=15

7 0
3 years ago
Answers for both boxes please :)​
NISA [10]

Answer: (-2;8)

\left \{ {{3x+3y=18} \atop {2x+y=4}} \right. \\\\\left \{ {{x+y=6} \atop {2x+y=4}} \right. \\\\=>\left \{ {{x=4-6} \atop {x+y=6}} \right. \\\\\left \{ {{x=-2} \atop {x+y=6}} \right. \\\\\left \{ {{x=-2} \atop {y=6-(-2)=8}} \right.

Step-by-step explanation:

6 0
3 years ago
I have 31 stamps in total. I have 4 more 1 cent stamps than 8 cent stamps and twice as many one cent stamps as 12 cent stamps. I
Neko [114]

Answer:

There area 14 one cent stamps

Step-by-step explanation:

Let

x -----> the number of 1 cent stamps

y -----> the number of 8 cent stamps

z -----> the number of 12 cent stamps

we know that

0.01x+0.08y+0.12z=1.78 -------> equation A

x=y+4 ------> y=x-4 -----> equation B

x=2z -----> z=0.5x ------> equation C

substitute equation B and equation C in equation A and solve for x

0.01x+0.08(x-4)+0.12(0.5x)=1.78

0.01x+0.08x-0.32+0.06x=1.78

0.15x=1.78 +0.32

0.15x=2.10

x=14

therefore

There area 14 one cent stamps

6 0
3 years ago
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