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Mademuasel [1]
3 years ago
11

parallelogram ABCD has vertices A(-2,-51/2), B(-4,-51/2), C(-3,-2), and D(-1,-2). find the vertices of parallelogram A'B'C'D' af

ter a translation of 2 1/2 units down.

Mathematics
1 answer:
Volgvan3 years ago
7 0
On a coordinate plane, any movement up and down is on the y-axis. So if your parallelogram is moving down 2.5 units, then the y-values of each vertice will go down by 2.5:
A(-2, -8), B(-4, -8), C(-3, -4.5), D(-1, -4.5)

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Joe went on holiday to Spain.
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a. £2,090
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Work for part a:

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1680+302.4=1982.4

1982.4/1.12 = £x/1

1982.4 / 1.12= £1,770

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Work for part b:
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Does 2^8 equal (3sqrt{16})^6
ale4655 [162]

Answer:

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Step-by-step explanation:

2⁸ = (3√16)⁶

Evaluate 2⁸. This can simply be written out as:

2 * 2 * 2 * 2 * 2 * 2 * 2 * 2

4 * 2 * 2 * 2 * 2 * 2 * 2

8 * 2 * 2 * 2 * 2 * 2

16 * 2 * 2 * 2 * 2

32 * 2 * 2 * 2

64 * 2 * 2

128 * 2

256.

256 = (3√16)⁶

Evaluate √16.

256 = (3*4)⁶

Multiply 3 and 4.

256 = 12⁶

Evaluate 12⁶. This can be rewritten as:

12 * 12 * 12 * 12 * 12 * 12

144 * 12 * 12 * 12 * 12

1728 * 12 * 12 * 12

20736 * 12 * 12

248832 * 12

2985984.

Since 256 ≠ 2985984, the answer to this question is no.

4 0
3 years ago
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