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sergejj [24]
3 years ago
11

Find the x intercepts for the parabola defined by the equation below. y=x^2-9x+18​

Mathematics
1 answer:
givi [52]3 years ago
7 0
X intercepts are where the y value is 0. So, set y=0 and solve
0=x^2-9x+18
0=(x-6)(x-3)
x=6,3
The x intercepts are (6,0) and (3,0)
if you want to check, try these (x, y) pairs in the original equation.
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Answer:

21 tribbles on the 7th night

Step-by-step explanation:

every night 3 tribbles appear meaning that the tribbles spawn rate is y=3x

y= number of tribbles

x= number of nights

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Which measurement is the best estimate for the distance between New York City and Washington, D.C.?
Black_prince [1.1K]
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In the figure at the right, what is the measure of angle c?<br> A.15<br> B.35<br> C.50<br> D.65
stealth61 [152]
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3 years ago
17-19, deal with the ambiguous SSA. For each, find all possible solutions and sketch the triangle(s) in each case
Tatiana [17]

The possible solutions using the Sine Law are given as follows:

Triangle A:
B = 50.26°

C = 79.74°

Triangle B:

B = 62.79°

C = 70.21°

<h3>What is the sine Rule?</h3>

The sine law asserts that the ratio of a triangle's side length to the sine of the opposing angle is the same for all three sides. The sine rule is another name for it.

<h3>What is the explanation for the above solution?</h3>

Triangle A

Given the sine law:
a/SinA = b/SinB

Hence

Sin B = (b/a) SinA

Sin B = 15/10 (Sin 50)

Sn B = (15/10) * 0.766

Sin B = 1.5 * 0.766

B = Sin⁻1 (1.14)

B = 50.26°

Hence, C =

180 - B - A

= 180 - 50.26 - 50

C = 79.74°

Solution B

Given the sine law:

a/SinA = b/SinB

Hence

Sin B = (b/a) SinA

Sin B = 2/1.6 (Sin 47)

Sn B = 1.25 * 0.73

Sin B = 0.9125

B = Sin⁻1 (0.9125)

B = 62.79°

Hence,

C = 180 - 62.79 - 47

C = 70.21°

Learn more about the Sine Law at;
brainly.com/question/12271113
#SPJ1

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2 years ago
A bus holds 25 students. There are 205 students. How many buses will be needed to transport all the students?​
Alja [10]

Answer:You would need 9 buses for everyone

Step-by-step explanation:with 8 buses you would have taken 200 students so you'd need one more bus for the other five.

8 0
3 years ago
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