Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
(X+12)^2 -18-(24/2)^2
(X+12)^2 -18-144
(X+12)^2-162
Your answer is 1.
Step-by-step explanation:
Find the gradient of AB
-2.5
Find the gradient of perpendicular
0.4
Make the equation
y= 0.4x + c
Apply point A
3= 0.4*2+c
3-0.8= c
c= 2.2
y= 0.8x + 2.2
Answer: The missing length is 120 {option C}
Step-by-step explanation: What we have in the question is a triangle placed on top of another triangle and as shown in the attached diagram we can separate them into triangles BFC and GFH.
A close observation shows that line BC is parallel to line GH. Hence we have two similar triangles, and we can determine their similarity ratios as follows;
BF/FC = GF/FH
Similarly BF/BC = GF/GH
We can also express the following ratio
FC/FH = BC/GH
Therefore to calculate the missing side, which is GF, we can use the ratio
FC/FH = FB/FG
30/100 = 36/FG
By cross multiplication we now have 30 (FG) = 100 (36)
30FG = 3600
Divide both sides of the equation by 30
FG = 120
Answer:
56
Step-by-step explanation:
