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Grace [21]
3 years ago
12

Bonita is testing prototype model rocket engines. To be considered a successful launch, the rocket must reach a height of at lea

st 24 ft and must go a horizontal distance of no more than 10 ft. The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.
The graph shows the feasible region, where x represents the horizontal distance and y represents the vertical distance.

Which ordered pairs meet all the constraints for a successful launch and make sense in context of the situation?

Select each correct answer.



(0, 33)

(4, 36)

(4.8, 30.5)

(9, 26)

(2, 22)

Mathematics
2 answers:
Reika [66]3 years ago
8 0
Refer to the diagram shown below.

The given constraints are
(a)  y ≥ 24 ft
(b ) x ≤ 10 ft
(c)  y ≥ 3x
(d)  y ≤ 33 ft
The acceptable region is shown shaded.

A (0, 33) satisfies all conditions
B (4, 36) fails condition (d)
C (4.8, 30.5) satisfies all conditions
D (9, 26) fails condition (c)
E (2, 22) fails condition (a)

Answer:
The acceptable points are A and C.

Virty [35]3 years ago
3 0
According to the questions, Conditions are
24 ≤ y ≤ 33
x ≤ 10
y ≥ 3x

So, (0, 33) & (4.8, 30.5)

Therefore, (0, 33) & (4.8, 30.5) are the correct answers.
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Elina [12.6K]

Answer:

-x^5+9x^4-18x^3=0\\-x^3(x^2-9x+18)=0\\-x^3(x-3)(x-6)=0\\\\\\\\x=0\\x=3\\x=6

4 0
4 years ago
Ajug contains 42 liters of milk. How
katovenus [111]

Based on the information given the number of milliliters of milk does it contain is 42,000 mL.

1 liter=1000 ml

Using this formula

Number of milliliters=Number of liters×1,000 ml

Where:

Number of liters=42 liters

Let plug in the formula

Number of milliliters=42 liters×1,000 ml

Number of milliliters=42,000 ml

Inconclusion  the number of milliliters of milk does it contain is 42,000 mL.

Learn more about milliliters here:brainly.com/question/1295017

6 0
2 years ago
How do you do this ​
Inessa [10]

Answer:

Nice one. I will give the answer!!

Step-by-step explanation:

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3 0
3 years ago
Find the factors of f(x) given that x = 5 is a zero.
77julia77 [94]
  • If x = 5 is a zero of the given polynomial, then,
  • (x - 5) is a factor of the polynomial. [Since, x = 5 or, x - 5 = 0]
  • Now, divide the polynomial with (x - 5) using long division method. (See the picture)
  • We get (x^2 - x - 6) as the quotient.
  • Now, factorise the above polynomial:
  • (x^2 - x - 6)
  • = (x^2 - 3x + 2x - 6)
  • = x(x - 3) + 2(x - 3)
  • = (x - 3)(x + 2)
  • Therefore, x^3 − 6x^2 − x + 30 = (x − 5)(x − 3)(x + 2)

<u>Answer</u><u>:</u>

<u>B.</u><u>(x − 5)(x − 3)(x + 2)</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
An earth satellite remains in orbit at a distance of 11550 km from the center of the earth. what speed would it have to maintain
marishachu [46]
<span>11,550 km has to be changed to 11,550,000 meters

G · m · t² = 4 · π² · r³  we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span> <span> <span> <span> 6.083*10^22 </span> </span> </span> <span><span> </span> </span> / <span> <span> <span> 3.9</span></span></span>9 * 10^14
t^2 =  <span> <span> <span> 152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers

Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which  <em>is 5,670 meters per second.</em>


Source:
http://www.1728.org/kepler3a.htm



4 0
4 years ago
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