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3 years ago

The cylinder shown has a volume of π in3. Find the volume of a cone with the same base and height as the cylinder

Mathematics

1 answer:

Luden [163]3 years ago

7 0

The volume would be 1/3π in³.

The volume of a cone is 1/3 the volume of a cylinder with the same radius and height.

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Solve the word problem. The table shows the low outside temperatures for Monday, Tuesday, and Wednesday. What was the change in

den301095 [7]

Answer: D. -3.2

Step-by-step explanation:

The correct answer to this question is D. -3.2 because when you subtract positive 8.8 and positive 12 your answer is -3.2.

(+8.8) - (+12) = -3.2

7 0

3 years ago

A square has an area of x^2-14x + 49cm2. What is the perimeter of the square?

kozerog [31]

Answer:

Step-by-step explanation:

6 0

2 years ago

EACH PAIR OF FIGURES IS SIMILAR. FIND THE MISSING SIDE!!!!

inessss [21]

Answer:

58.1 and 17

Step-by-step explanation:

For the first triangles the similarity ratio is 1:7 so x is 8.3 × 7 = 58.1

For the second triangles the similarity ratio is 1:5 so x is 3.4 × 5 = 17

8 0

3 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago

What equation is the equation of the line that passes through (-10,8) and (5,5)

Fofino [41]

The equation of the line is given by

y = mx + c

where m is the gradient of the line
c is where the line cuts the y-axis
x & y represent coordinates on the line.

The gradient m can be obtained as follows:

m = (5 - 8) / (5 - - 10) = (-3) / (15) = - 1/5

To obtain c, we use any known coordinate on the line and substitute it as well as the gradient in the general equation for the line.

Taking coordinates (5,5)

5 = (- 1/5)(5) + c

5 = - 1 + c

c = 6

Hence, the equation for this line is

y = -x/5 + 6

6 0

3 years ago