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makvit [3.9K]
3 years ago
12

All answers choices are the same please help

Mathematics
1 answer:
OleMash [197]3 years ago
7 0
1. alternate Interior angles
2. ?
3. alternate interior angles
4.Alternate exterior angles
5.?
6. alternate exterior angles
(sorry that’s what i know)
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Hi can someone please answer this question? <br><br> Thank you :)
Archy [21]

Answer:

\frac{7}{8}

Step-by-step explanation:

Remember that slope, or in this case pitch, is equal to rise divided by run. In other words:

m=\frac{rise}{run}

where m is the slope.

From looking at the image, we can see that the rise 21 feet and the run is 24 feet. By plugging this information into the equation, we get:

m=\frac{21}{24}=\frac{7}{8}

So the slope, or pitch, of the roof id 7/8.

I hope you find my answer and explanation to be helpful. Happy studying.

7 0
3 years ago
The polygon in the diagram is a regular octagon with center A. Find the area of the octagon to the nearest tenth of a foot. A) 2
IRISSAK [1]
Method 1: In order to find out the area of an octagon with a radius of 4 feet, we have to split the whole figure into 8 equal isosceles triangles.
Therefore, 
We will find out the area of one triangle and multiply the area with 8 to, figure out the area of the whole octagon there are 8 similar triangles and all of them will have the same area.

Method 2: From method 1, it would take time as there are too much of calculation, therefore we would go for the shortcut using the formula:

Area = 2√2 × r²

where r<span> is the radius of the octagon.
Substituting the values,
We get:
             </span>Area = 2√2 × 4²
             Area = 2√2 × 16
             Area = 2× 1.41 × 16 
             Area = 2.828 × 16 
            Area = 45.25

Rounded to the nearest tenth:

Area = 45.3 ft²


4 0
3 years ago
Find the length of the unknown side. Round your number to the nearest tenth.
spin [16.1K]
The length of the unknown side is 17.5
3 0
3 years ago
Can someone please explain how to solve this? And give me the answer?! THANK U !
Lyrx [107]

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76

4 0
3 years ago
A bus traveled 150 mlles in 3 hours. At what average rate did the bus travel?
dezoksy [38]

50 Miles at an average rate

8 0
3 years ago
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