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Serjik [45]
3 years ago
5

Nonspecific permeases a. allow a variety of molecules to cross the cytoplasmic membrane. b. allow only water to cross the cytopl

asmic membrane. c. are not used for passive transport. d. allow only one type of solute to pass through the membrane.
Biology
1 answer:
andriy [413]3 years ago
3 0

Answer:

a. allow a variety of molecules to cross the cytoplasmic membrane

Explanation:

The cells have different molecules in its membrane. As a membrane the main function of it is to regulate the income and outcome of substances that the cell needs or the cell has like some wastes.

Some of these molecules can be some proteins like the permeases, that is going to  regulate the solutes that can enter the cell, but since they are non specific, that means that can not make the difference among one carbohydrate and another (as an example).

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What is not true regarding fenestrated capillaries?
dangina [55]

The question is incomplete. The complete question is as follows:

Which of the following is not true regarding fenestrated capillaries?

A) Fenestrated capillaries in endocrine organs allow hormones rapid entry into the blood.

B) Fenestrated capillaries in the small intestine receive nutrients from digested food.

C) Fenestrated capillaries are essential for filtration of blood plasma in the kidney.

D) Fenestrated capillaries form the blood-brain barrier.

Answer:

Fenestrated capillaries form the blood-brain barrier.

Explanation:

The fenesterated capillaries are small fine thin capillaries that helps in the exchange of substances. These capillaries are mainly found in the kidney, small intestine and glands.

The fenestrted capillaries allow the exchnage of hormone in the blood and in the kidney for the filtration. The nutrients can be easily exchanged by the capillaries present in the small intestine. The blood brain barrier function is not performed by the fenesterated capillaries. They allows the rapid exchange function and not as the barrier.

Thus, the correct answer is option (D).

8 0
3 years ago
The scientific name of an organism is made up of its ____________. It is written in at italics (Genus Species) with the genus ca
tester [92]
Genes,all organisms are identified by their genomes in the big picture
4 0
3 years ago
Which of the following is NOT an adaptation for deep diving in Cetaceans? Having a lot of myoglobin in the muscles to store oxyg
kifflom [539]

Answer:

Hence the correct answer is Blood flow is shifted from the brain to the extremities.

Explanation:

Blood flow is shifted from the brain to the extremities - most marine mammals have an in-depth network of blood vessels towards their brain which is understood because of the retia mirabilia. These reduce the temperature in the extremities.

8 0
3 years ago
In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The gene
NikAS [45]

Answer:

A) 9:3:3:1

B) All bitter fruit, yellow spotted offsprings

C) Phenotypes are bitter yellow spotted (4), bitter no spot (4), sweet yellow spot (4), and sweet no spot (4). 1:1:1:1

Explanation:

This is a typical dihybrid cross involving two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

Hence, a heterozygous F1 resulting from a cross between an homozygous dominant (bitter fruit, yellow spot) and homozygous recessive (sweet fruit, no spot) will have a BbSs genotype. The heterozygous F1 offsprings are self-crossed and produce gametes BS, Bs, bS, bs. (See punnet square). The F2 offsprings will have the following phenotypes: Bitter fruit, yellow spot (9)

Bitter fruit, no spot (3)

Sweet fruit, yellow spot (3)

Sweet fruit, no spot (1)

Back cross between a F1 offspring (BbSs) and homozygous dominant parent (BBSS) will produce all bitter fruit, yellow spot offsprings (see attached image). BBSS (4), BBSs (4), BbSS (4), and BbSs (4) are the offsprings' genotypes.

For the back cross between a F1 offspring (BbSs) and a homozygous recessive (bbss) parent, the Phenotypes with their proportions are as follows:

Bitter fruit, yellow spot (BbSs, 4)

Bitter fruit, no spot (Bbss, 4)

Sweet fruit, yellow spot (bbSs, 4)

Sweet fruit, no spot (bbss, 4).

4 0
3 years ago
In humans tongue rolling is dominant to the inability to tongue roll. If a heterozygous tongue roller and a non-tongue roller ha
ella [17]
In humans, tongue rolling is dominant to the inability to tongue roll. The chances a child will be a non-tongue roller is C. 0.5.
3 0
3 years ago
Read 2 more answers
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