Question

Please help! Which is not equal to the others?

Answer 1

Answer:

C

Step-by-step explanation:

Given

a sinxcosx

b

$\frac{1}{2}$ sin2x = $\frac{1}{2}$ × 2sinxcosx = sinxcosx

c

sin²x × $\frac{cos^2x}{sin^2x}$ = cos²x

d

$\frac{sinx}{cosx}$ × cos²x = sinxcosx

Hence c is the expression not equal to the others

Answer 2

The answer would be C.
Sin2 cot2=sin2*cos2/sin2=cos2
Which is not equal to the others.
Hope this helps:)