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Sonja [21]
3 years ago
13

In physics class, Carrie learns that a force, G, is equal to the mass of an object, m, times its acceleration, a. She writes the

equation as G = ma, then realizes that each of her homework problems asks her to solve for acceleration. She rewrites the formula as = a. Using this formula, what is the acceleration of an object with F = 7.92 newtons and m = 3.6 kilograms? Express your answer to the nearest tenth.
Mathematics
2 answers:
kap26 [50]3 years ago
7 0

Answer:

2.2

Step-by-step explanation:

wlad13 [49]3 years ago
6 0

Your problem statement is missing the formula Carrie came up with. It should be The one she started with, divided by m.

... G/m = a

For the values given, the acceleration is

... (7.92 N)/(3.6 kg) = 2.2 m/s²

_____

The unit of newtons is abbreviated N.

1 N = 1 kg·m/s² so dividing by kilograms leaves units of m/s², which are the units of acceleration.

Very likely, your question is not concerned with the units, just the number: 2.2. It's a straight division problem, easily handled by hand, by calculator, or in your head (after you realize 7.92 = 7.2×1.1 = 2×3.6×1.1).

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Which of the following is equivalent to 2x2 + 9x + 9?
valkas [14]

Answer:

(x+3)(2x+3)

Step-by-step explanation:

Factor:

2x^2+9x+9

=(2x+3)(x+3)

8 0
3 years ago
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Is the polynomial prime? <br> 7x2-35x+2x-10
wolverine [178]

The given polynomial is not a prime polynomial.

Given the polynomials, we have to choose the polynomial which is prime.

A polynomial with integer coefficients that cannot be factored into lower degree polynomials is Prime polynomials.

7x^2-35x+2x-10

7x^2-33x-10

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

<h3>What is the formula for the quadratic roots?</h3>

\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=7,\:b=-33,\:c=-10

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

x_{1,\:2}=\frac{-\left(-33\right)\pm \:37}{2\cdot \:7}

x_1=\frac{-\left(-33\right)+37}{2\cdot \:7},\:x_2=\frac{-\left(-33\right)-37}{2\cdot \:7}

x=5,\:x=-\frac{2}{7}

Therefore the factor is (x-5) and (7x+2).

can be factored

∴ not a prime polynomial.

To learn more about the prime polynomial visit:

brainly.com/question/26388060

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4 0
2 years ago
F(x)=x 3−9xf, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 9, x What is the average rate of change of f over
mel-nik [20]

Answer:

A(x) = 243

Step-by-step explanation:

Given

f(x) = x^3 - 9x

Interval: (12,6)

Required

Determine the average rate of change

Average rate is calculated as thus;

A(x) = \frac{f(b) - f(a)}{b - a}

<em>In this case; b = 12 and a = 6</em>

Calculating f(12)

f(12) = 12^3 - 9 * 12

f(12) = 1728 - 108

f(12) = 1620

Calculating f(6)

f(6) = 6^3 - 9 * 6

f(6) = 216 - 54

f(6) = 162

Substitute 12 for b and 6 for a in A(x) = \frac{f(b) - f(a)}{b - a}

A(x) = \frac{f(12) - f(6)}{12 - 6}

Substitute values for f(6) and f(12)

A(x) = \frac{1620 - 162}{12 - 6}

A(x) = \frac{1458}{ 6}

A(x) = 243

4 0
3 years ago
What is the area of this trapezoid? Enter your answer in the box.
olga2289 [7]
The formula for area of a trapezoid is
\frac{(b1 + b2) \times h}{2}
so you add up the bottom base (17) and the top base (3) to get 20.
you then take the sum of the bases (20) times the height (8) to get 160.
lastly, you take 160 ÷ 2 to get your final answer, which is 80 (:
4 0
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Three dice are rolled. Let the random variable x represent the sum of the 3 dice. By assuming that each of the 63 possible outco
tamaranim1 [39]
<h3>Answer:  1/8</h3>

In decimal form, 1/8 = 0.125 which converts to 12.5%

==================================================

Work Shown:

The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.

Here are all of the ways to add to 11 if we had 3 dice

  1. sum = 1+4+6 = 11
  2. sum = 1+5+5 = 11
  3. sum = 1+6+4 = 11
  4. sum = 2+3+6 = 11
  5. sum = 2+4+5 = 11
  6. sum = 2+5+4 = 11
  7. sum = 2+6+3 = 11
  8. sum = 3+2+6 = 11
  9. sum = 3+3+5 = 11
  10. sum = 3+4+4 = 11
  11. sum = 3+5+3 = 11
  12. sum = 3+6+2 = 11
  13. sum = 4+1+6 = 11
  14. sum = 4+2+5 = 11
  15. sum = 4+3+4 = 11
  16. sum = 4+4+3 = 11
  17. sum = 4+5+2 = 11
  18. sum = 4+6+1 = 11
  19. sum = 5+1+5 = 11
  20. sum = 5+2+4 = 11
  21. sum = 5+3+3 = 11
  22. sum = 5+4+2 = 11
  23. sum = 5+5+1 = 11
  24. sum = 6+1+4 = 11
  25. sum = 6+2+3 = 11
  26. sum = 6+3+2 = 11
  27. sum = 6+4+1 = 11

There are 27 ways to add to 11  using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.

So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.

7 0
3 years ago
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