Which point lies on a circle with a radius of 5 units and center at P(6, 1)?
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Answer:
Step-by-step explanation:
This is our quadratic:
where s(t) is the position of the object after all the stuff on the right side happens to it. If the object lands on the ground after all that stuff happens to it, its height is 0. Subbing in a 0 for s(t) gives us:
and if the object hits the ground at 21 seconds, we can sub in a 21 for each t to get this:
and do the math.
and solving for the height:
h = 1845.9 meters
The question is not clear but I will solve it for all the possible conditions.
If cosФ = - √37 ÷ 6
Which means,
Adjacent = - √37
Hypotenuse = 6
This is not possible because hypotenuse cannot be smaller.
If cosecФ = - √37 ÷ 6
Which means,
Opposite = 6
Hypotenuse = - √37
Using Pythagoras theorem,
Adjacent = (Hypotenuse)² - (Opposite)²
Adjacent = √{(- √37)² - (6)²}
Adjacent = √{(37 - 36}
Adjacent = √{(1}
Adjacent = 1
Now we have all the three sides of a right triangle, therefore, we can find out the value for cotФ.
That is;
cotФ = adjacent ÷ opposite
cotФ =
If cosФ = - √37 ÷ 6
Which means,
Adjacent = - √37
Hypotenuse = 6
This is not possible because hypotenuse cannot be smaller.
If cosecФ = - √37 ÷ 6
Which means,
Opposite = 6
Hypotenuse = - √37
Using Pythagoras theorem,
Adjacent = (Hypotenuse)² - (Opposite)²
Adjacent = √{(- √37)² - (6)²}
Adjacent = √{(37 - 36}
Adjacent = √{(1}
Adjacent = 1
Now we have all the three sides of a right triangle, therefore, we can find out the value for cotФ.
That is;
cotФ = adjacent ÷ opposite
cotФ =