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matrenka [14]
3 years ago
14

Which point lies on a circle with a radius of 5 units and center at P(6, 1)?

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
For a circle with radius 'r' ad center, (h,k)
the formula is

(x-h)²+(y-k)²=r²

(6,1)
r=5
(x-6)²+(y-1)²=5²
(x-6)²+(y-1)²=25
hmm
when x=6, then y=6
a point is (6,6)
also (6,-4)
also (1,1)
also (11,1)
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3 years ago
Y = 4x-9<br> y = x-3<br> Which method and why? Solve, shoving all work
vodomira [7]

Answer:

(2,-1)

Step-by-step explanation:

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===============

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2 years ago
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Step-by-step explanation:

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The answers are

11. c) 7x² +5x +8 remainder 7.

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Step-by-step explanation:

Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.

Step 2; By dividing 6x^{4} +0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6x^{4} +6x³. We subtract this from 6x^{4} +0x³ and get -6x³. Now we add this with the -3x² in 6x^{4} +0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.

4 0
3 years ago
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