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2 years ago

10

96 = 12d A. 108 B. 84 C. 8 D. −1 8

2 answers:

Gnesinka [82]2 years ago

8 0

Answer:

I dont know

Step-by-step explanation:

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Tpy6a [65]2 years ago

4 0

Answer:

Step-by-step explanation:

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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree

Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

$\cos A=\dfrac{b^2+c^2-a^2}{2bc}$

Using Law of Cosines in triangle OPQ, we get

$\cos P=\dfrac{o^2+q^2-p^2}{2oq}$

$\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}$

$\cos P=\dfrac{490000+384400-705600}{868000}$

$\cos P=\dfrac{168800}{868000}$

On further simplification, we get

$\cos P=0.19447$

$P=\cos^{-1}(0.19447)$

$P=78.786236$

$P\approx 79$

Therefore, the measure of angle P is 79 degrees.

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3 years ago

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Alla [95]

the first answer is 14

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3 years ago

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7nadin3 [17]

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2 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

Divide both sides by -2.

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2 years ago