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Ad libitum [116K]
3 years ago
12

An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes)

, one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?
Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0
23 differrent dinners

adoni [48]3 years ago
3 0

Answer:

There are 400 ways to choose the dinner.

Step-by-step explanation:

Since we have to choose one dish from each column and we have three columns A ,B and C .

Number of choices for Column A = 8

Number of choices for column B = 10

Number of choices for column C = 5 dishes

Number of different family dinners can be chosen = 8x10 x5

                                                                                     = 400 ways

                                                [Using fundamental principle of Multiplication]

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