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Ad libitum [116K]
3 years ago
12

An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes)

, one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?
Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0
23 differrent dinners

adoni [48]3 years ago
3 0

Answer:

There are 400 ways to choose the dinner.

Step-by-step explanation:

Since we have to choose one dish from each column and we have three columns A ,B and C .

Number of choices for Column A = 8

Number of choices for column B = 10

Number of choices for column C = 5 dishes

Number of different family dinners can be chosen = 8x10 x5

                                                                                     = 400 ways

                                                [Using fundamental principle of Multiplication]

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17x-3y=4 2x-4y=1 the solution to the system of equations is
Burka [1]

ANSWER

x=\frac{13}{62}

and


y= \frac{-9}{62}e have



EXPLANATION




17x-3y=4---(1)


2x-4y=1



Let us make y the subject and call it equation (2)


2x=1+4y


x=\frac{1}{2}+2y--(2)



We put equation (2) in to equation (1)




17(\frac{1}{2}+2y)-3y=4


\frac{17}{2}+34y-3y=4



34y-3y=4- \frac{17}{2}


Simplify to get,



31y= \frac{8-17}{2}



31y= \frac{-9}{2}


Divide both sides by 31,



y= \frac{-9}{2} \div 31



y= \frac{-9}{2} \times \frac{1}{31}




y= \frac{-9}{62}


We put this value in to equation (2) to get,



x=\frac{1}{2}+2\times -\frac{9}{62}




x=\frac{1}{2} -\frac{18}{62}


We collect LCM to obtain,



x=\frac{31-18}{62}



x=\frac{13}{62}








7 0
3 years ago
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12). Find the probability of rolling a
levacccp [35]

Answer:

P(x>12) = 0

Step-by-step explanation:

Given

x = \{1,2,3,4,5,6,7,8,9,10,11,12\} --- outcomes

n(x) = 12 -- sample size

Required

P(x > 12)

This is calculated as:

P(x > 12) = \frac{n(x > 12)}{n(x)}

n(x>12) = 0 because none of the outcomes is greater than 12:

So:

P(x > 12) =\frac{0}{12}

P(x>12) = 0

6 0
3 years ago
Solve each system of equations by graphing y=2/3x+3 3y=2x+15
dangina [55]

Answer:

There is no solution to that equation.

Step-by-step explanation:

First thing to do is to put the second equation in terms of y. To do so the equation becomes y= 2/3x+5. Comparing those two equation you can see that the slopes are the same and thus means that the system has no solution.

Another way to see this is by graphing both of thee equations is a calculator and seeing there are no points of intersection.

7 0
3 years ago
Is -1 a solution to 4x - 3 &lt; 5?<br> (look at the picture)
inessss [21]

Answer:

Yes

Step-by-step explanation:

Assuming that the question is asking for -1 to be plugged in as x

4(-1)-3≤5

-4-3≤5

-7≤5

5 0
2 years ago
What is the answer for this question?
grandymaker [24]

Answer:

A

Step-by-step explanation:

\frac{11\pi }{6} is in the fourth quadrant where tan < 0

The related acute angle = 2π - \frac{11\pi }{6} = \frac{\pi }{6}

Hence

tan( \frac{11\pi }{6} )

= - tan(\frac{\pi }{6} )

= - \frac{1}{\sqrt{3} }

= - \frac{1}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} }

= - \frac{\sqrt{3} }{3} → A

5 0
3 years ago
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