Answer:
See below ~
Step-by-step explanation:
Given :
⇒ m∠1 = m∠2
⇒ HD = GF
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To Prove :
<u>Δ EHD ≅ Δ EGF</u>
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Solving :
⇒ m∠1 = m∠2 (Given)
⇒ HD = GF (Given)
⇒ ∠E = ∠E (Common angle)
⇒ ΔEHD ≅ ΔEGF (AAS congruence)
Answer:
Step-by-step explanation:
We have been given that the rectangle has an area of 
square meters and a length of 
. We are asked to find the width of rectangle.
Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.
Upon substituting our given values in above formula we will get,
Using exponent rule for quotient 
we will get,
Therefore, width of our given rectangle will be 9x meters.
Divide centimeters by 100. Answer is 1.52 meters.
Answer:
The answer is C because the constant ratio of y/x is 12/5
Answer:
D. When its angles are right angles.
Step-by-step explanation:
A rhombus can be a rectangle when its angles are right angles.
