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mestny [16]
4 years ago
10

List four ways a person can withdraw money from a checking account.

Physics
1 answer:
dmitriy555 [2]4 years ago
8 0
1. By using an ATM to withdraw money with a debit card
2. By using an ATM to withdraw money with a credit card
3. Going in the bank and requesting a withdrawal 
4. Using a bank app to withdraw money
You might be interested in
Physicist Max Planck showed how objects like stars give off different colors based on their temperature. What color are the hott
jenyasd209 [6]

Answer:

the brightest found are Blue - White with

Explanation:

The energy emission of objects increases with their temperature, specifically Wien described the process in an expression

 

          \lambda_{maximum} T = 2,898 10⁻³

With this expression we can find the temperature of the stars by the color they emit.

Specifically the Sun has a color of 550 nm which corresponds to 5400K

bright stars have a BLUE color corresponding to 7500K

the brightest found are Blue - White with a temperature of 20000K

7 0
3 years ago
An object is 15 cm in front of a diverging lens with a
Rainbow [258]

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

4 0
4 years ago
Does a greater amount of force always result in a greater amount of work? Why or why not? Does moving an object a greater amount
Zina [86]
Thank you for posting your question here at brainly. I would say yes to the above question. <span>Work done is the force applied multiplied by the distance travelled. </span><span>Wd = F x d. </span><span>So if d increases, Wd increases also. I hope the answer will help you. </span>
5 0
3 years ago
A 66.0−kg short-track ice skater is racing at a speed of 10.0 m/s when he falls down and slides across the ice into a padded wal
dexar [7]

Answer:

3300J

Explanation:

Work done is the energy that is lost by the skater

Formula for workdone = 1/2*mV^2

m = 66kg

V = 10m/s

Work done = 1/2 * 66 * 10^2

= 3300J

7 0
3 years ago
in a tall building, a certain window is 500 meters above the ground.A tennis ball is catapulted horizontally out of the window w
expeople1 [14]

The tennis ball lands at a point 40.4 m from the base of the building.

The tennis ball is projected with a horizontal velocity <em>u</em> from a window, which is at a height <em>y</em> from the ground. The ball lands at a distance <em>x</em> from the base of the building. Let the ball take a time <em>t</em> to reach the ground. In the time <em>t</em> ,the ball falls a vertical distance <em>y</em> and also travel a horizontal distance <em>x</em>.

The initial vertical velocity of the ball is zero, since the ball is projected in the horizontal direction.  The ball falls down under the action of gravitational force.

Thus, use the equation of motion,

y=\frac{1}{2} gt^2

rewrite the expression for <em>t</em> and calculate the value of <em>t</em> using 9.81 m/s²for <em>g</em> and 500 m for <em>y</em>.

t=\sqrt{\frac{2y}{g} } \\ =\sqrt\frac{(2)(500m)}{9.81m/s^2}  \\ =10.096 s

The horizontal distance <em>x</em> is traveled using the constant velocity <em>u </em>since no force acts on the ball in the horizontal direction.

Therefore,

x=ut

Substitute 4 m/s for <em>u</em> and 10.096 s for <em>t</em>

x=ut\\ =(4m/s)(10.096s)\\ =40.384m=40.4 m

Thus, the ball lands at a point 40.4 m from the base of the building.



6 0
3 years ago
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