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Contact [7]
3 years ago
12

10-kg box is sliding across an ice rink at 10 m/s . A skater exerts a constant force of 10 N against it. How long will it take f

or the box to come to a complete stop?
Physics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

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What carries an electric current through a solution?
sashaice [31]
Free ions. Negative ions have one extra electron, positive ions are missing an electron. Negative ions give up their extra electron easily. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions. 
8 0
3 years ago
A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on
telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m

The work done by gravity on the boy is calculated as;

W = P.E = mgh

             = 32kg x 9.8m/s² x 1.928m

             = 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0
3 years ago
If the period of a certain wave (wavelength = 4.5 m) is 2 seconds, what is the speed of the wave?
taurus [48]

Answer:

2.25m/s

Explanation:

wavelength=4.5m

period=2sec

frequency= 1/period

=1/2

speed= wavelength×wave frequency

=4.5×1/2

=2.25 m/s

so, none of the options are correct

5 0
3 years ago
The cheetah, the fastest of land animals, can run a distance of 274 m in 8.65 s at its top speed. What is the cheetahs tips spee
ycow [4]

Answer:

Top speed is 31.68 m/s

Explanation:

Speed of a body is the distance traveled by the body in unit time.

Speed is generally expressed in meter per second or kilometer per hour.

Here, the cheetah travels a distance of 274 m in 8.65 s.

Therefore, speed of cheetah is the distance traveled by it in one second.

For 8.65 s, distance traveled is 274 m

For 1 s, distance traveled will be \frac{274}{8.65} meters per second. This value is called speed.

So, speed is given as the ratio of the distance traveled to that of the time taken.

∴ Top speed of cheetah is given as:

v_{max}=\frac{274}{8.65}=31.68 \textrm{ m/s}

Here, v_{max} is the top speed of cheetah.

7 0
4 years ago
A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle
NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area,A=0.344 m^2

Drag coefficient,C_d=0.88

Coefficient of rolling resistance,\mu_r=0.007

Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

Drag force,F_d=\frac{1}{2}\rho_{air}AC_dv^2

Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

1 m=0.00062137 miles

1 hour=3600 s

7 0
4 years ago
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