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3 years ago

15. A machine must move an object 15.1 meters by exerting a 121 Newton force. If the machine

Physics

1 answer:

Tcecarenko [31]3 years ago

6 0

The power provided by the machine is 13.24 W.

Answer:

Explanation:

Power is determined as the ratio of work done by the system or on the system to the time interval. As the work done is equal to the product of force acting on the system or by the system with the displacement experienced by the system. The power provided by the machine will be

Power = Work done /Time

As the force is given as 121 N and the displacement is given as 15.1 m in a time interval of 2.3 minutes. The time interval should be changed to seconds for each solving ability.

Time taken = 2.3 * 60 s = 138 s

Power = (121×15.1)/138 = 13.24 W.

So the power provided by the machine is 13.24 W.

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A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block

MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

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