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Sonbull [250]
3 years ago
6

15. A machine must move an object 15.1 meters by exerting a 121 Newton force. If the machine

Physics
1 answer:
Tcecarenko [31]3 years ago
6 0

The power provided by the machine is 13.24 W.

Answer:

Explanation:

Power is determined as the ratio of work done by the system or on the system to the time interval. As the work done is equal to the product of force acting on the system or by the system with the  displacement experienced by the system. The power provided by the machine will be

Power = Work done /Time

As the force is given as 121 N and the displacement is given as 15.1 m in a time interval of 2.3 minutes. The time interval should be changed to seconds for each solving ability.

Time taken = 2.3 * 60 s = 138 s

Power = (121×15.1)/138 = 13.24 W.

So the power provided by the machine is 13.24 W.

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A block rests on a frictionless horizontal surface and is attached to a spring. When set into simple harmonic motion, the block
MariettaO [177]

Answer:

v₀ = 0.5058 m/s

Explanation:

From the question, for the block to hit the bottle, the elastic potential energy of the spring at the bottle (x = 0.08 m) should be equal to the sum of the elastic potential energy of the spring at x = 0.05 m and the kinetic energy of block at x = 0.05 m

Now, the potential energy of the block at x = 0.08 m is ½kx²

where;

k is the spring constant given by; k = ω²m

ω is the angular velocity of the oscillation

m is the mass of the block.

Thus, potential energy of the spring at the bottle(x = 0.08 m) is;

U = ½ω²m(0.08m)²

Also, potential energy of the spring at the bottle(x = 0.05 m) is;

U = ½ω²m(0.05m)²

and the kinetic energy of the block at x = 0.05 m is;

K = ½mv₀²

Thus;

½ω²m(0.08)² = ½ω²m(0.05)² + ½mv₀²

Inspecting this, ½m will cancel out to give;

ω²(0.08)² = ω²(0.05)² + v₀²

Making v₀ the subject, we have;

v₀ = ω√((0.08)² - (0.05)²)

So,

v₀ = 8.1√((0.08)² - (0.05)²)

v₀ = 0.5058 m/s

7 0
3 years ago
Please help me out! Thanks! (:
ElenaW [278]

X=Ft is a possible equation for X because by using SI units its final term became Kg metre per second

3 0
3 years ago
Where is earth's magnetic north pole located?
andre [41]

Answer: it is located over Ellesmere Island, Canada

Explanation

it is now drifting away from North America and toward Siberia.

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If the mass of an egg is 0.57kg and it is dropped, calculated the force using newton's 2nd law
nlexa [21]

F = ma

Acceleration in this case is acceleration due to gravity so

a = 9.8 m/s^2

and mass = 0.57kg

So..

F = (0.57)(9.8)

F = 5.586 or 5.56 N

8 0
3 years ago
Consider the hydrogen atom as described by the Bohr model. The nucleus of the hydrogen atom is a single proton. The electron rot
riadik2000 [5.3K]

To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

a_c = \omega^2 r

Here,

\omega =Angular velocity

r = Radius

Our values are given as,

\omega = 4.12*10^{16}rad/s

r = 5.29*10^{-11}

Replacing,

a_c = (4.12*10^{16})^2( 5.29*10^{-11})

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Therefore the electron's centripetal acceleration is 8.979*10^{22}m/s^2

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