Answer:
a5=445
Explanation:
a of n=(a+1)*n
a1=2
I found the pattern to add 1 to the previous number and then multiply it by its number in the sequence. Apologies for the terrible format of my recursive formula.
Proof of pattern:
(2+1)*2=6
(6+1)*3=21
(21+1)*4=88
a5=(88+1)*5=445
That would be choice C the limit of f(x) is 2.
Answer:
25x⁴y⁶
Step-by-step explanation:
From what I understand your question looks like this
(5x²y³)²
To solve this just mulitply
5x²y³*5x²y³

25x⁴y⁶
Answer:
Assuming the repetitive part is 152, i.e. the original repeating decimal is
A=3.152152152....
then
1000A=3152.152152152152....
subtract A
1000A-A=3152.152152....-3.152152152....
999A=3149
A=3149/999=3+152/999=3 152/999
Therefore
3.152152152.... = 3149/999 or 3 152/999