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Ber [7]
3 years ago
11

Darrin is hanging 200 feet of Christmas garland on the fencing that encloses his rectangular front yard. The length is 5 feet le

ss than 5 times the width. Find the length and width of the fencing. Give the measurements in decimal form.
Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

Length = 82.5 feet

Width = 17.5 feet

Step-by-step explanation:

The formula for the Perimeter of a rectangle = 2(Length + Width)

= 2L + 2W

We are told in the question that: Darrin is hanging 200 feet of Christmas garland on the fencing that encloses his rectangular front yard

Hence, The perimeter of the rectangular front yard = 200 feet

200 = 2( L + W).........Equation 1

Also, the length is 5 feet less than 5 times the width

L = 5W - 5

Hence,

200= 2(5W - 5 + W)

200 = 2(5W + W - 5)

200 = 2(6W - 5)

200 = 12W - 10

Collect the like terms

200 + 10 = 12W

210 = 12W

W = 210/12

W = 17.5 feet

Substitute 17.5 for W in Equation 1

200 = 2( L + W).........Equation 1

200 = 2( L + 17.5)

200 = 2L + 35

200 - 35 = 2L

2L = 165

L = 165/2

L = 82.5 feet

Therefore, the Length of the rectangular fence = 82.5 feet while the Width of the rectangular fence is 17.5 feet.

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