All categories

3 years ago

What is the slope line that would be parallel to the given line???

Mathematics

1 answer:

Serjik [45]3 years ago

6 0

Slope of a line parallel to given line is equal to slope of given line.

SOLUTION:

Given that, we have to find the slope of any line that is parallel to a line in the co – ordinate plane.

We know that, slope of a line is tan( angle of a line made between that line and the x – axis)

So, consider two lines which are parallel , then, angles made by both the parallel lines will be equal with the x – axis.

Then, tan( angle by 1st line) = tan( angle by 2nd line)

Which means that, slope of two lines will be equal.

Hence, slope of a line parallel to given is equal to slope of given line.

You might be interested in

Whoever gets this right gets brainliest

lorasvet [3.4K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Pls help due in 15 mins

solmaris [256]

1) y = 8 x = 7.5
2) y = 3 x = 12

5 0

3 years ago

Read 2 more answers

I need help with this too

DiKsa [7]

Answer:

Angle HFG + angle ACB = 90°

Angle EFC = Angle DFG

Angle HFG + angle DFH = angle DFG

= 90°

The answer is B Angle DFH = angle ACB

Hope this helps!

7 0

4 years ago

You decide to erect A statue of yourself in your homeroom class is 10.25 feet tall fire code forces you to leave 1.5 feet of spa

seraphim [82]

H is less than or equal to 8.75

5 0

3 years ago

According to an NRF survey conducted by BIGresearch, the average family spends about $237 on electronics (computers, cell phones

Usimov [2.4K]

Answer:

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is 0.0537.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is 0.0023.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is 0.1101.

Step-by-step explanation:

We are given that according to an NRF survey conducted by BIG research, the average family spends about $237 on electronics in back-to-college spending per student.

Suppose back-to-college family spending on electronics is normally distributed with a standard deviation of $54.

Let X = back-to-college family spending on electronics

SO, X ~ Normal( $\mu=237,\sigma^{2} =54^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean family spending = $237

$\sigma$ = standard deviation = $54

(a) Probability that a family of a returning college student spend less than $150 on back-to-college electronics is = P(X < $150)

P(X < $150) = P( $\frac{X-\mu}{\sigma}$ < $\frac{150-237}{54}$ ) = P(Z < -1.61) = 1 - P(Z $\leq$ 1.61)

= 1 - 0.9463 = 0.0537

The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9463.

(b) Probability that a family of a returning college student spend more than $390 on back-to-college electronics is = P(X > $390)

P(X > $390) = P( $\frac{X-\mu}{\sigma}$ > $\frac{390-237}{54}$ ) = P(Z > 2.83) = 1 - P(Z $\leq$ 2.83)

= 1 - 0.9977 = 0.0023

The above probability is calculated by looking at the value of x = 2.83 in the z table which has an area of 0.9977.

(c) Probability that a family of a returning college student spend between $120 and $175 on back-to-college electronics is given by = P($120 < X < $175)

P($120 < X < $175) = P(X < $175) - P(X $\leq$ $120)

P(X < $175) = P( $\frac{X-\mu}{\sigma}$ < $\frac{175-237}{54}$ ) = P(Z < -1.15) = 1 - P(Z $\leq$ 1.15)

= 1 - 0.8749 = 0.1251

P(X < $120) = P( $\frac{X-\mu}{\sigma}$ < $\frac{120-237}{54}$ ) = P(Z < -2.17) = 1 - P(Z $\leq$ 2.17)

= 1 - 0.9850 = 0.015

The above probability is calculated by looking at the value of x = 1.15 and x = 2.17 in the z table which has an area of 0.8749 and 0.9850 respectively.

Therefore, P($120 < X < $175) = 0.1251 - 0.015 = 0.1101

5 0

4 years ago