4 also 2 :))))))))))))))))
Hello :
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
Answer:
y=2/-1+8
Step-by-step explanation:
- -4= (-4,0) -4=x1 0=y1, 8= (0,8) 0=x2 8=y2
- formula is, y2-y1/x2-x1
- 8-0/0-4=8/-4=4/-2= 2/-1
- 2/-1 is the slope or (m), use (-4,0) or (0,8) i used (0,8) because its easier.
- (0,8), 0=x1 8=y1
- formula is y-y1=m(x-x1)
- y-8=2/-1(x-0) ---->distribute
- y-8=2/-1x-0 --->get y alone
+8 +8
- so the answer is y=2/-1+8
Answer:
x > 2/3
Step-by-step explanation:
-4(3x - 5) < 2(3x + 4)
Divide both sides by 2.
-2(3x - 5) < 3x + 4
Distribute on the left side.
-6x + 10 < 3x + 4
Subtract 3x from both sides.
-9x + 10 < 4
Subtract 10 from both sides.
-9x < - 6
Divide both sides by -9. Remember that when you divide both sides of an inequality by a negative number, the inequality sign changes direction.
x > (-6)/(-9)
x > 6/9
x > 2/3
A line that is tangent to each of the two coplanar circles
