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zhuklara [117]
4 years ago
12

PLEASE HELP ME!!!!!!

Mathematics
1 answer:
Sauron [17]4 years ago
7 0

Answer:

50.24

Step-by-step explanation:

pi times r^2

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Is 8000 meters greater than 9 kilometers?
mrs_skeptik [129]

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no

Step-by-step explanation:

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1 year ago
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What expression is equivalent to the square root of -80
Ganezh [65]

Answer:

Step-by-step explanation:

√-80

7 0
3 years ago
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G(x) = 13.2x³ + 3x4 -x-4.4
Kisachek [45]

The given polynomial has a degree of 4, the leading coefficient is 3, and the constant is 4.4.

<h3>What is a polynomial?</h3>

A polynomial is an algebraic expression with terms that are the combination of variables, coefficients, and constants.

  • The highest power of the variable is said to be the degree of the polynomial.
  • The coefficient of the highest power variable is said to be the leading coefficient.

<h3>Calculation:</h3>

The given polynomial is

g(x) = 13.2x³ + 3x⁴ - x - 4.4

The highest power of the variable x is 4. So, the degree of the variable is 4.

Then, the leading coefficient is 3.

The constant on the given polynomial is 4.4.

Learn more about polynomials here:

brainly.com/question/1600696

#SPJ9

Disclaimer: The given question on the portal was incomplete. Here is the complete question.

Question: For the given polynomial, identify the degree, leading coefficient, and the constant value.

g(x) = 13.2x³ + 3x⁴ - x - 4.4

3 0
2 years ago
Find the degree of the monomial. 3x^8y^4<br> A.4<br> B.8<br> C.3<br> D.12
ioda
There are 3 degrees
 in this monomial
8 0
4 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
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