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zhuklara [117]
3 years ago
12

PLEASE HELP ME!!!!!!

Mathematics
1 answer:
Sauron [17]3 years ago
7 0

Answer:

50.24

Step-by-step explanation:

pi times r^2

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john and ted have a reputation of being late to events. If john is late 20% of the time and ted is late 40% of the time what is
oee [108]

Answer:

The probability that they will both be on time is 12/25.

Step-by-step explanation:

John is late 20% of the time.

So, he is prompt 80% of the time.

Ted is late 40% of the time.

So, he is prompt 60% of the time.

Since, both the events are independent,

p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)

= \frac{80}{100} × \frac{60}{100}

= 0.80 × 0.60

= 0.48 or 48%

=\frac{12}{25}

Hence, the probability that they will both be on time is 12/25.

3 0
3 years ago
Again, please help. i dont know any of this
Levart [38]

\textrm {Cylinder volume :}

\mathrm {Volume = \pi r^{2}{h}}

\mathrm {Volume = 3.14 \times (\frac{4}{2})^{2} \times 3}

\mathrm {Volume = 3.14 \times 12}

\mathrm {Volume = 37.68cm^{3}}

\textrm {Rectangular prism volume :}

\mathrm {Volume = length \times width \times height}

\mathrm {Volume = 6 \times 5 \times 7}

\mathrm {Volume = 30 \times 7}

\mathrm {Volume = 210cm^{3}}

\textrm {Total volume of composite figure :}

\textrm {Volume of cylinder + volume of rectangular prism}

\mathrm {37.68 + 210}

\mathrm {247.68cm^{3}}

4 0
1 year ago
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In an arithmetic sequence, if you are given a3=93 and a5=135, find a=100. Must show work to receive full credit.
Elanso [62]

The 100th term of the sequence is 2130.

<h3>How to calculate the value?</h3>

a3 = a + 2d = 93

a5 = a + 4d = 135

Compute both equations

(4d - 2d) = (135 - 93)

2d = 42

d = 42/2 = 21

a + 2d = 93

a + 2(21) = 93

a + 42 = 93

a = 94 - 42 = 51

100th term will be:

= a + 99d

= 51 + 99(21)

= 51 + 2079

= 2130

Learn more about sequence on:

brainly.com/question/6561461

#SPJ1

5 0
1 year ago
Simply this plz ո • ո3
anzhelika [568]

Answer:

Answer is n^4

Step-by-step explanation:

You add the exponent when they are multiplying and have the same base

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2 years ago
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Luke has a bag of 70 colored marbles. The bag has an equal number of green and blue marbles and an equal number of red and yello
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It could be over 9000 but its actually 11<span />
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