Part A: The answer is PR = 15.23 by Pythagorean Theorem.
The pythagorean theorem is a^2 + b^2 = c^2.
Plug in 14 for a and 6 for b to find c.
Part B: The answer is QR = 7.75.
Using the same theorem, plug 16 in for c, 14 in for a, and then you can find b.
Answer:
See below.
Step-by-step explanation:
1.
Statement 8. triangle SQR is congruent to triangle TQP
Reason 8. ASA
2.
The only way to prove those two sides are congruent is to first prove that the triangles that contain those sides are congruent. Then you can use CPCTC to prove those sides congruent.
Answer:
41
Step-by-step explanation:
Given x = -2,
Substitute x into the expression.
C^2 - 10c = 0
c^2 - 10c + 25 = 25
(c - 5)^2 = 25
c - 5 = sqrt 25
c = 5 (+-) sqrt 25
c = 5 (+-) 5
c = 5 + 5 = 10
c = 5 - 5 = 0
solutions are 0,10
Answer:
A, B and C.
Step-by-step explanation:
If its a right triangle then c^2 = a^2 + b^2 where a, b and c are the 3 sides, c being the hypotenuse.
3^2 + 6^2 = 9 + 36 = 45
and (√45)^2 = 45 so the first set (A) is a right triangle.
2.5^2 + 6^2 = 6.25 + 36 = 42.25.
6.5^2 = 42.25 so B is also a right triangle.
C:
4^2 + 8^2 = 16 + 64 = 80
(√80)^2 = 80 so C is right-angled also.
