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3 years ago

HELP ASAP I CAN ONLY DO THIS ONE TIME OR ILL FAIL

Mathematics

2 answers:

docker41 [41]3 years ago

7 0

Answer:

Step-by-step explanation:

V= BxHxL divided by 2

6x9x21= 1,134

divided by 2 equals 567yd

Sergeeva-Olga [200]3 years ago

6 0

Answer:

A) 567 yd^3

Step-by-step explanation:

If you need help with formulas you could always look them up. Like triangular prism volume formula

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A triangle has a base of (3x + 7) and a height of (5x - 1). A second

Mars2501 [29]

Answer:

The difference between the area of the original triangle and the area of the new triangle is $\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)$ .

Step-by-step explanation:

The equation for the area of a triangle ( $A_{\bigtriangleup}$ ) is:

$A_{\bigtriangleup} = \frac{1}{2}\cdot b \cdot h$

Where:

$b$ - Base, dimensionless.

$h$ - Height, dimensionless.

The expression for each triangle are described below:

First Triangle ( $b = 3\cdot x + 7$ , $h = 5\cdot x - 1$ )

$A_{\bigtriangleup,1} = \frac{1}{2}\cdot (3\cdot x+7)\cdot (5\cdot x -1)$

Second Triangle ( $b = 3\cdot (3\cdot x+7)$ , $h = 2\cdot (5\cdot x -1)$ )

$A_{\bigtriangleup,2} = 3\cdot (3\cdot x+7)\cdot (5\cdot x -1)$

The difference between the area of the original triangle and the area of the new triangle is:

$\Delta A_{\bigtriangleup} = A_{\bigtriangleup,2}-A_{\bigtriangleup,1}$

$\Delta A_{\bigtriangleup} = 3\cdot (3\cdot x+7)\cdot (5\cdot x-1)-\frac{1}{2} \cdot (3\cdot x+7)\cdot (5\cdot x-1)$

$\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)$

The difference between the area of the original triangle and the area of the new triangle is $\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)$ .

7 0

3 years ago

What is (3 plus 1/2) times 12

Fynjy0 [20]

9 is the answer!!!!!!!!!!!!!!!!!!!!!!

5 0

3 years ago

Read 2 more answers

Use the elimination method to solve the system of equations choose the correct ordered pair x-3y=-23 5x+6y=74

Sloan [31]

Answer:

( 4, 9 ) is our solution in an ordered pair, as you could also say x = 4, and y = 9

Step-by-step explanation:

So we have the following system of equations at hand ( given directly below ), and want to make it such that each equation is multiplied by a value that makes a common variable, say x, have opposite values of coefficients such that they cancel each other out when the two equations are added, enabling you to solve for the value of the other variable, in this case variable y.

$\begin{bmatrix}x-3y=-23\\ 5x+6y=74\end{bmatrix}$ - Multiply this top equation by -5, so the coefficient of variable x becomes - 5, opposite to the respective x coefficient in the second equation.

$\begin{bmatrix}-5x+15y=115\\ 5x+6y=74\end{bmatrix}$ - Adding the two equations we receive the simplified equation 21y = 189. y = 189 / 21 = 9. If y = 9, x should = - 23 + 3y = - 23 + 3 $*$ 9 = 4. To get this value of x simply isolate the value of x in the first equation given to us, and substitute the known value of y. We have our solution in the form ( 4, 9 ), where x = 4 and y = 9.