<span>Let's say you divide 25 by 4. You will get a quotient 6, but have that remainder of 1. You could also divide 37 by 6, and likewise get a quotient of 6, with a remainder of 1. The difference is that the remainders are not truly the same. The first remainder is 1 part out of 4, but the second remainder is 1 part out of 6</span>
Answer:
gof(x) = 3
Step-by-step explanation:
Given that,
f(x) = x+2 and g(x) = x+1
We need to find gof(x).
gof(x) means g[f(x)].
g[f(x)] = g(x +2)
= x+2+1
= x+3
Hence, the value of gof(x) is 3.
Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.
Since there are two dice, the total possible outcome is 36.
Hence, the probability of getting one number each is 1/36
Hence, the principal used a fair method because each result is an equally likely possible outcome.
Option B is correct.
Whats ur question? Are u trying to figure out x ?
Answer:
Step-by-step explanation:
3(m-2)+2(m-2)
3m-6+2m-4
3m+2m-6-4
5m-6-4
5m-10
The expressions 3(m-2)+2(m-2) and 50m-2 are not equivalent expressions.
After simplifying the first expression 3(m-2)+2(m-2) in part (a), we got 5m-10, which is different from the second expression, 50m-2.
