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IceJOKER [234]
3 years ago
15

Standard form for -10-6x^4-7x^2+5x

Mathematics
1 answer:
qaws [65]3 years ago
7 0
-6x^4-7x^2+5x-10. hope this helps ! :)
You might be interested in
55 points
cupoosta [38]

Answer:

160:40 or 160 to 40, 80:320 or 80 to 320, 400:1000 or 400 to 1000

Step-by-step explanation:

4 0
3 years ago
Is this correct? the question is asking if the triangle would have a right, acute, or obtuse angle.
IgorLugansk [536]

Answer:

ut ok points from me so I took it from u

6 0
3 years ago
A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
Each leg of a 45 45 90 triangle measures 12cm, what is the length of the hypotenuse
erastova [34]

Answer:

12√2

Step-by-step explanation:

Use the Pythagorean Theorem here:

(12 cm)^2 + (12 cm)^2 = 288 cm^2.  

The length of the hypotenuse is √288 = (√4)(√72) = 2(√36)(√2) = 12√2

8 0
3 years ago
Read 2 more answers
How do you graph x + y= -2?
iris [78.8K]
Graph the line using the slope and y-intercept, or two points.
Slope:
−
1
-
1
Y-Intercept:
−
2
-
2
x
y
0
−
2
1
−
3
Please mark BRAINLIEST ❤️

8 0
3 years ago
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