Answer:
Mutations are only passed on to offspring when they occur in germ cell DNA, which are the cells that create sperm or ova. The other kind of cells, somatic cells, are the rest of the cells in the body, and mutations that occur in these cells do not get passed on to offspring.
Explanation:
i had the same thing for health
Explanation:
What would cause a tree to die?
There are 5 factors to which a tree eventually succumbs: death from its environment, death from harmful insects and diseases, death from a catastrophic event, death from age-related collapse (starvation) and of course, death from harvest.
I hope this helps
Competition factor are the species of birds responding to in the environment. Thus, the correct option is B.
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What is competition?</h3>
If numerous bird species eat on the same tree species, there will be fierce competition for food. As a result of the competition, each species will seek out a certain portion of the plant to feed on, most likely the part of the plant where it will be easiest to outcompete the competitors for food.
As a result, we may deduce that the right response is "They have evolved to diverse niches as a result of competition."
For more information regarding competition, visit:
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Answer:
1.Blood pressure in the small capillaries pushes the fluid into a sack called Bowman's capsule. 2. It reabsorbs important nutrients that are in the filtrate. 3. The Loop of Henle descends from the cortex into the medulla and concentrations of salts in the interstitium increases. 4. Salts leave the filtrate using both passive and active diffusion. 5. Waste products ammonia and urea are transported into the filtrate for excretion, while calcium and sodium continue to be reabsorbed and water leaves the nephron. 6. The filtrate empties into collecting ducts, where it combines with filtrate from other nephrons.
Answer:
Explanation:
From the question, the total population = 171 i.e (80+71+21)
Genetic frequency therefore; BB = 71/171 = 0.42
Bb = 80/171 = 0.47
bb = 20/171 = 0.12
Allele frequency therefore;
Allele B = 0.42+(0.50×0.47) = 0.66
Allele b = (0.50×0.47)+0.12 = 0.36
Note all values were rounded up to two significant figures
