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4 years ago

Help please! Math 1: Please explain it LOTS OF POINTS!!!

Mathematics

2 answers:

stiv31 [10]4 years ago

8 0

I think it is 52 as well.

eimsori [14]4 years ago

7 0

I think that the answer is extremely close to 52 square feet. I hope it helps!

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suppose that F(x)=x^2 and G(x)=(1/4x)^2. Which statement best compares the graph of g(x) with the graph of f(x)

Vsevolod [243]

Answer:

g(x) is the image of f(x) after stretched horizontally by scale factor = 4

Step-by-step explanation:

The statement that best compares the graph of g(x) with the graph of f(x) says g(x) is the image of f(x) after stretched horizontally by scale factor = 4 because:

Given the function

f(x) = x² and g(x) = (1/4x)² the image of f(x) after one transformation.

The transformation shows that g(x) stretches away from y-axis.

Since the transformation is stretched horizontally. So g(x) is the image of f(x) after stretched horizontally by scale factor (I.e. by 1).

Then we use the scale factor to divide g(x)

1 ÷ ¼ = 1 x 4/1 = 4

So therefore, g(x) is the image of f(x) after stretched horizontally by scale factor = 4

5 0

4 years ago

Malika, Keshia, and Aliyah Smith are each 2 years apart in age. The sum of their ages is greater than the age of their father, w

VikaD [51]

Answer:

24?

Step-by-step explanation:

If you add 20, 22, and 24, you get 66. I dont know if this helped.

5 0

3 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.)

Valentin [98]

Answer:

attached below

Step-by-step explanation:

The Function; F(x) = x^2 / (x^4 + 81 )

power series representation

F(x) = x^2 / ( 81 + x^4 )

= ( x^2/81 ) / 1 - ( -x^4/81 )

attached below is the remaining part of solution

6 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

When will 4a ≤ 16 be true?

Artist 52 [7]

Answer:

It will be true when a ≤ 4

Step-by-step explanation:

You can plug in the number to see if it is correct. 4(4) ≤ 16. Sorry, I'm not the best at explaining things.

7 0

4 years ago