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zhenek [66]
3 years ago
12

I am a real number I am a rational number I am not a natural number I am less than -13 what number am I

Mathematics
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

Any number less than -13.

Step-by-step explanation:

If the number is real and rational and non-natural, this means that it can be any number in the negative number space.

Additionally, since the number has to be less than -13, then the number could be any number less than -13.

With all these things considered, the number is any number less than -13 that is real and rational.

Cheers.

kicyunya [14]3 years ago
3 0
It’s -13 because it either can be less or more
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Dado dos ángulos complementarios, uno mide (2x + 10) y el otro (x + 20),
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Answer:

El valor de <em>x</em> es igual a 20 o <em>x</em> = 20.

Step-by-step explanation:

Lo primero que se debe saber es que <em>dos ángulos complementarios suman un ángulo recto o 90º</em>.

Supongamos que el valor de un ángulo \\ \alpha y un ángulo \\ \beta valen:

\\ \alpha = 2x + 10 [1]

\\ \beta = x + 20 [2]

Como la suma de  \\ \alpha + \beta = 90 [3]

Entonces

\\ \alpha + \beta = (2x + 10) + (x + 20) = 90

Sumamos los factores comunes entre si:

\\ (2x + x) + (10 + 20) = 90

Para la primera expresión debemos recordar que se suman sólo los coeficientes. Así:

\\ (2 + 1)x + (10 + 20) = 90

\\ 3x + 30 = 90

Para despejar la incógnita <em>x</em>, debemos tener en cuenta que <em>una igualdad no se altera si se suma, se resta, se multiplica o divide un mismo valor a cada lado de ella</em>. Por esta razón, para despejar 3x, lo primero que podemos hacer es sumar -30 a cada lado de la expresión (lo que es igual a restar 30 a cada lado de la misma). Así tenemos:

\\ 3x + 30 - 30 = 90 - 30

\\ 3x + 0 = 90 - 30

\\ 3x = 60

Ahora dividimos cada miembro de la igualdad entre 3 (o multiplicamos cada lado de la igualdad por \\ \frac{1}{3} ):

\\ \frac{3}{3}x = \frac{60}{3}

Como sabemos que:

\\ \frac{3}{3} = 1

Entonces:

\\ 1*x = \frac{60}{3}

\\ x = \frac{60}{3}

\\ x = 20

De esta manera, el valor de <em>x</em> es igual a 20 o x = 20.

Lo anterior lo podemos comprobar considerando las ecuaciones [1], [2] y [3]. Así tenemos que:

\\ \alpha = 2x + 10 [1]

Sustituimos x por el valor de 20:

\\ \alpha = 2*20 + 10 = 40 + 10 = 50

\\ \beta = x + 20 [2]

Hacemos lo mismo para [2]:

\\ \beta = 20 + 20

\\ \beta = 40

De esta manera:

\\ \alpha + \beta = 90 [3]

\\ 50 + 40 = 90

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