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4 years ago

I am a real number I am a rational number I am not a natural number I am less than -13 what number am I

Mathematics

2 answers:

tresset_1 [31]4 years ago

8 0

Answer:

Any number less than -13.

Step-by-step explanation:

If the number is real and rational and non-natural, this means that it can be any number in the negative number space.

Additionally, since the number has to be less than -13, then the number could be any number less than -13.

With all these things considered, the number is any number less than -13 that is real and rational.

Cheers.

kicyunya [14]4 years ago

3 0

It’s -13 because it either can be less or more

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4-4x=12+16x will gib brainleist i promise ;)

Delicious77 [7]

Answer:

4-4x=12+16x

−4x+4=16x+12

−4+4−4=16+12−4

-4x=16x+8

-4x-16x=16x+8-16x

-20x=8

-20x/-20 = 8/-20

x= -2/5

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3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

8 0

3 years ago

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Lilit [14]

Plug the value of 9 in for y
9=-3x+6

Subtract 6 from both sides
3=-3x

Divide both sides by -3
-1=x

Final answer: x=–1

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3 years ago

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Mrac [35]

The answer would be angles UVX and RSQ.
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3 years ago

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musickatia [10]

Answer:

Your answer choice is correct.

Step-by-step explanation:

The length of the semicircle is ...

s = π·r = π(4 in)

The three sides of the rectangular section total ...

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The sum of these lengths make up the perimeter of the figure:

P = 4π in + 26 in

P = (4π +26) in

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3 years ago