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ivolga24 [154]
3 years ago
10

A rectangle has a length of 10ft.and a width of 6ft.whats the perimeter

Mathematics
2 answers:
Delicious77 [7]3 years ago
5 0
Add 10 + 10 + 6 + 6 = 32
32 ft.
Novay_Z [31]3 years ago
3 0
60 becaus eyou take the l times the w and you get 60
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Help please, will give thanks uwu
BabaBlast [244]

(3x) + (x+60) = 180

4x + 60 = 180

Subtract 60 from both sides

4x = 120

Divide 4 from both sides

x = 30

7 0
3 years ago
Read 2 more answers
F(x)=12x2-4x-8. G(x)=11x-6
AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

f(x)=12x^2-4x-8\\\\g(x)=11x-6

You need to divide them in order to find (\frac{f}{g})(x) asked in the exercise. Then:

(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

11x-6=0

2. Finally, you must solve for "x":

11x=6\\\\x=\frac{6}{11}

Therefore, as you can see, the answer is:

 (\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}, x=\frac{6}{11}

4 0
3 years ago
Simplify the power of i^15
TiliK225 [7]

Answer:

this cant be simplified unless you have an integer in place of "i"

4 0
3 years ago
Read 2 more answers
How can i solve this ?
ExtremeBDS [4]

Answer: X > 100

Step-by-step explanation:

X - 19 < 81

Once the less than sign is turned over

X > 81 +19

X > 100

Thus, the value of X must be greater than 100

6 0
3 years ago
Cones A and B both have volume cubic 48 π units, but have different dimensions. Cone A has radius 6 units and height 4 units. Fi
Alex_Xolod [135]

Answer:

A possible solution is that radius of cone B is 2 units and height is 36 units

Step-by-step explanation:

The volume of a cone is given by

V=\frac{1}{3}\pi r^2 h

where

r is the radius

h is the height

Here we are told that both cones A and B have the same volume, which is:

V_A=\frac{1}{3}\pi r_A^2 h_A = 48 \pi

And

V_B=\frac{1}{3}\pi r_B^2 h_B = 48 \pi (2)

We also know that cone A has radius 6 units:

r_A=6

and height 4 units:

h_A=4

For cone B, from eq.(2), we get

\frac{1}{3}r_B^2 h_B = 48\\r_B^2 h_B = 48\cdot 3 =144

One possible solution for this equation is

r_B = 2\\h_B = 36

In fact in this case, we get:

r_B^2 h_B = (2)^2\cdot 36 = 4\cdot 36 = 144

Therefore a possible solution is that radius of cone B is 2 units and height is 36 units, and we know that in this case Cone B has the same volume as cone A because it is told by the problem.

6 0
2 years ago
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