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aev [14]
2 years ago
15

If the area of a square is 32 ft2, how long is its diagonal?

Mathematics
1 answer:
Tema [17]2 years ago
7 0

Diagonal = 8

D=diagonal

A=area

A=D^/2

32=D^/2

32/1 = D^/2

cross multiplication

32x2=D^x1

64=D^

8 =D




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Mathew ran 3/8 mile and then walked 7/10 mile which pair of fractions can he use to find how far he went in all
jeka57 [31]

Answer:

15/40 and 28/40

Step-by-step explanation:

3/8 = 15/40

7/10 = 28/40

15+28=43

1 3/40

(I wasn't sure what the question really wanted)

xx

5 0
3 years ago
HELP PLZ
enot [183]

(f.g)(x) = f (g(x))= f ( x^4+3)

= (x^4+3)^2 + 2 ( x^4+3) - 6

= x^8 + 9 + 6x^4 + 2x^4 + 6-6

= x^8 + 8x^4+9

7 0
3 years ago
In a recent year, the ACT scores for the math portion of the test were normally distributed, with a mean of 21.1 and a standard
Natali5045456 [20]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

c) P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

d) We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(21.1,5.3)  

Where \mu=21.1 and \sigma=5.3

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

Part c

P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

Part d

We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

6 0
3 years ago
If the consumer price index changes from 125 in september to 150 in october, what is the rate of inflation?
allochka39001 [22]
The rate of inflation is analogous to the percent difference of the original to the new price. Thus, its formula is written as:

Rate of Inflation = [New price - Base price]/Base Price * 100
Rate of inflation = (150 - 125)/125 * 100 = 20%

<em>So, the answer is A.</em>
4 0
3 years ago
Read 2 more answers
Which equation correctly describes the relationship between the measures of the angle and arcs formed by the intersecting secant
marishachu [46]
Angle m∠1 if formed by a tangent and  secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant 
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)

Answer: m∠1=1/2(mJK-KL)
3 0
3 years ago
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