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Ne4ueva [31]
3 years ago
11

Problem page an 11 - ft ladder leans against the side of a house. the bottom of the ladder is 8 ft from the side of the house. h

ow high is the top of the ladder from the ground? if necessary, round your answer to the nearest tenth.
Mathematics
1 answer:
Lisa [10]3 years ago
5 0
A^2 + b^2 = c^2
8^2 + b^2 = 11^2
64 + b^2 = 121
b^2 = 121 - 64
b^2 = 57
b = sqrt 57
b = 7.54 rounds to 7.5 ft <==
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If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?
Ber [7]

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The triangle should be 16 inches wide.

Step-by-step explanation:

\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2

What we know:

  • One of the legs measures 12 inches.
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We need to solve for b. Solving for a while b is 12 would also be acceptable.

12^2 + b^2 = 20^2  \text {  OR  }   a^2 +12^2=20^2

We will use the first equation.

12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}

\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}

The triangle should be 16 inches wide.

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3 years ago
HELP will give brainliest if all correct
ladessa [460]

1. Definition of Parallelogram

2. Angle 2 plus Angle 3 is 180=Def of Supple

3.Angle Congruence Postulate

4. Angle 1 and Angle 3 equal to 180

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