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Lelu [443]
4 years ago
10

Tanya wants to order 50 pizzas for a party. However, the pizza supplier can deliver only 45 pizzas on the given date. How will y

ou describe the relationship between demand and supply of pizzas?
Mathematics
2 answers:
lesya [120]4 years ago
8 0
Supply is 45 pizzas

demand is 50 piizas

the demand is greater than the supply
the customer will probably be willing to pay more for the same amount of pizzas
saul85 [17]4 years ago
4 0

Answer:

Demand was more than supply

Step-by-step explanation:

we have to understand the situation between demand and supply

Here in the given case requirement of pizza was 50 that is demand of pizza

And delivery bot can deliver only 45 pizzas

That s demand of pizza was 50 and supply was 45.

Demand was more than supply


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The height of Mountain Pis 1,086 feet. The height of Mountain Q is 4 times the
Afina-wow [57]

Answer:

4,344 feet

Step-by-step explanation:

Mt. P is 1,086 feet tall. It says that Mt. Q is 4 times that. 1,086 x 4 is 4,344.

5 0
2 years ago
Read 2 more answers
.. Which of the following are the coordinates of the vertices of the following square with sides of length a?
atroni [7]

Option A: O(0,0), S(0,a), T(a,a), W(a,0)

Option D: O(0,0), S(a,0), T(a,a), W(0,a)

Step-by-step explanation:

Option A: O(0,0), S(0,a), T(a,a), W(a,0)

To find the sides of a square, let us use the distance formula,

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now, we shall find the length of the square,

\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}

Thus, the square with vertices O(0,0), S(0,a), T(a,a), W(a,0) has sides of length a.

Option B: O(0,0), S(0,a), T(2a,2a), W(a,0)

Now, we shall find the length of the square,

\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}

This is not a square because the lengths are not equal.

Option C: O(0,0), S(0,2a), T(2a,2a), W(2a,0)

Now, we shall find the length of the square,

\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}

Thus, the square with vertices O(0,0), S(0,2a), T(2a,2a), W(2a,0) has sides of length 2a.

Option D: O(0,0), S(a,0), T(a,a), W(0,a)

Now, we shall find the length of the square,

\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}

Thus, the square with vertices O(0,0), S(a,0), T(a,a), W(0,a) has sides of length a.

Thus, the correct answers are option a and option d.

8 0
3 years ago
Find an equation equivalent to r = 10 sinθ in rectangular coordinates
Flura [38]

Answer:

x^{2} + y^{2} - 10\cdot y = 0

Step-by-step explanation:

The following expressions are used to transform from polar into rectangular form:

r = \sqrt{x^{2}+y^{2}}

\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}

Now, the variables are substituted and equation is finally simplified:

\sqrt{x^{2}+y^{2}} = 10\cdot \frac{y}{\sqrt{x^{2}+y^{2}} }

x^{2}+y^{2} = 10\cdot y

The equivalent equation in rectangular coordinates is:

x^{2} + y^{2} - 10\cdot y = 0

8 0
3 years ago
CAN YOU HELP WITH THIS ONE QUESTION , JUST TRYING TO GET BACK ON HONOR ROLL !
Ivanshal [37]

Answer:

B. TRUE.

(3, 2) is the intersection point of the graphs of

x + y = 5 and x - y = 1.

Step-by-step explanation:

Option B is TRUE because intersection point should satisfy both the equation

and in option be it comes true.

i.e x = 3  and y = 2 we have

3 + 2 = 5 and  3 - 2 = 1

5 = 5       and    1 = 1

Hence TRUE

A.

(3, 2) is the intersection point of the graphs of

3x + 2y = 5 and 3x - 2y = 1.

i.e x = 3  and y = 2 we have

3×3 + 2×2 = 5 and 3×3 - 2×2 = 1

13 ≠ 5               and 5 ≠ 1

Hence FALSE

C.

(5, 1) is the intersection point of the graphs of

3x + 2y = 5 and 3x - 2y = 1.

i.e x = 5  and y = 1 we have

3×5 + 2×3 = 5 and 3×5 - 2×3 = 1

21 ≠ 5               and  9 ≠ 1

Hence FALSE

D.

(5, 1) is the intersection point of the graphs of

x + y = 5 and x - y = 1.

i.e x = 5  and y = 1 we have

5 + 1 = 5 and 5 - 1 = 1

6 ≠ 5      and 4 ≠ 1

Hence FALSE

6 0
3 years ago
Identify the semiregular tessellation. HELP ASAP. PLEASE I AM DESPERATE!!
nignag [31]

Answer:

  see below

Step-by-step explanation:

A <em>regular tessellation</em> involves repeated use of a single regular polygon to cover the plane.

A <em>semiregular tessellation</em> involves repeated use of <em>two or more</em> regular polygons (in the same order around each polygon vertex) to cover the plane.

The first and third diagrams do not involve regular polygons. The fourth involves only a single regular polygon. Hence the second diagram is the one of interest.

7 0
3 years ago
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