Answer:
B
Step-by-step explanation:
Answer:
<u>Line b</u>
Step-by-step explanation:
It cannot be line a or line d because the line will have a constant rate of change. It cannot be line c because line c would be undifined. Therefore, it must be line b.
Answer:
x=-1
y=4
z=7
Step-by-step explanation:
3x + y - z= -6(1)
2x - y + 2z = 8(2)
4x + y - 3z = -21(3)
(1)+(2): 5x+z=2(4)
(2)+(3): 6x-z=-13(5)
(4)+(5): 11x=-11
x=-1
so z=2-5x=7
y=-6-3x+z=4
Answer:
Step-by-step explanation:
Apply the Pythagorean Theorrem. Find the sum of the squares of the two shortest sides and determine whether this sum equals the square of the longest side:
#19: 5^2 + 12^2 = ? = 13^2
25 + 144 = ? = 169 This is true, so you do have a right triange in #19.
#21: 2^2 + 4^2 = ? = 7^2, or 4 + 16 = ? = 49 This is false. Not a right
triangle.
Apply this same approach (Pythagorean Theorem) to the remaining problems.
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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