Answer:
4+b
Step-by-step explanation:
Answer: option A. 30 °.
Explanation:
1) Draw this triangle: Eyes - Ship A - height of the cliff:
The angle of the vertix where the eyes are is: 90° - depreesion angle = 90° - 60° = 30°.
2) opossite leg = horizontal distance to the ship A = x
3) adjacent leg = height of the cliff = 1500 feet
4) tan(30°) = x / 1500 feet => x = 1500 tan(30°) = 1500 √3 / 3 = 500√3
5) Draw the triangle of the eyes - ship B - hieght of the cliff
6) The unknown is the depression angle of the eyes with ship B, α
7) opposite leg = 500√3 feet + 1000√3 feet = 1500√3 feet
8) adjacent leg = height of the cliff = 1500 feet
9) tan(α) = opposite leg / adjacent leg = 1500√3 / 1500 = √3
10) α = arctan(√3) = 60°
11) Depression angle = 90° - 60° = 30° Which is the answer
The sum of -5a and 3 is greater than 1.
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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Perimeter = 0.75 * 3 = 2.25 <span>inches</span>
