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3 years ago

Solve for x 4 x- >6x+8

Mathematics

1 answer:

finlep [7]3 years ago

5 0

So you're suppose to isolate the variable by dividing each side by factors that don't contain the variable.

Which equals or at least.. Makes x = − 4

____

I hope this helps, as always. I wish you the best of luck and have a nice day, friend..

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Why do you sometimes need to regroup in 3 digit addition problems

SCORPION-xisa [38]

Because for example 349+567 is something you need to regroup.You start by the ones.9+7=16. You don't always need to regroup though

6 0

3 years ago

Can someone tell me the answer for 11

Shtirlitz [24]

1. y=x+3
2. y=x+3
3. y=2x+8

p.s. please leave a thanks

4 0

4 years ago

The diagram represents a 12 cm by 4 cm rectangle.

LenaWriter [7]

The answer is 48.

A= Hight x Width

Multiply 12 x 4 and you will get 48.

6 0

3 years ago

The volume of ice-cream in the cone is half the volume of the cone. The cone has a 3 cm radius and

zhannawk [14.2K]

Answer:

h = 5 cm

Step-by-step explanation:

Given that,

The volume of ice-cream in the cone is half the volume of the cone.

Volume of cone is given by :

$V_c=\dfrac{1}{3}\pi r^2h$

r is radius of cone, r = 3 cm

h is height of cone, h = 6 cm

So,

$V_c=\dfrac{1}{3}\pi (3)^2\times 6\\\\V_c=18\pi\ cm^3$

Let $V_i$ is the volume of icecream in the cone. So,

$V_i=\dfrac{18\pi}{2}=9\pi\ cm^3$

Let H be the depth of the icecream.

Two triangles formed by the cone and the icecream will be similiar. SO,

$\dfrac{H}{6}=\dfrac{r}{3}\\\\r=\dfrac{H}{2}$

So, volume of icecream in the cone is :

$V_c=\dfrac{1}{3}\pi (\dfrac{h}{2})^2(\dfrac{h}{3})\\\\9\pi=\dfrac{h^3}{12}\pi\\\\h^3=108\\\\h=4.76\ cm$

h = 5 cm

So, the depth of the ice-cream is 5 cm.

8 0

4 years ago

Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will

muminat

Ella has 0.5 lbs of sugar. 75% syrup

Percent of mass = $\frac{mass of solute}{mass of solution} * 100$

Let the mass of solution is x

Given mass of solute = 0.5

percent of mass = 75

75 = $\frac{ 0.5}{x} * 100$

75x = 0.5 * 100

75 x = 50

x = 0.67

Mass of solution = 0.67

Mass of water = mass of solution - mass of solute (sugar)

= 0.67 - 0.5 = 0.17

So 0.17lb of water is added with 0.5lb of sugar to get 0.67lb of solution.

8 0

4 years ago